),fill=False,contours=30)
c = a + b
c
Thanks. This isn't imperative by any means. I was just going through
some old notebooks from last semester.
-Sterling
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Ah, yes, I forgot the variable y. Regardless, I still get a math
domain error that wasn't present before.
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Is this the optimal code for what I'm trying to do? On my MacBook, it
takes a good minute or so before the graph appears. Not that I'm
complaining...
On Nov 21, 9:56 pm, Robert Bradshaw rober...@math.washington.edu
wrote:
On Nov 21, 2009, at 7:50 PM, Jason Grout wrote:
Sterling wrote
really pretty. Any suggestions?
Thanks,
Sterling
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When I use numpy to calculate the norm, this works fine:
linalg.norm(y, ord=2)
But if I want to use:
linalg.norm(y, ord=inf)
NameError: name 'inf' is not defined. What am I doing wrong?
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Now how do I evaluate f itself at those same points. I can't seem to
figure it out.
On Sep 24, 9:47 pm, Jason Grout jason-s...@creativetrax.com wrote:
Sterling wrote:
How do I evaluate a Jacobian at certain values? For example, I type:
x1,x2,x3 = var('x1 x2 x3')
f1(x1,x2,x3) = 3*x1
How do I evaluate a Jacobian at certain values? For example, I type:
x1,x2,x3 = var('x1 x2 x3')
f1(x1,x2,x3) = 3*x1 - cos(x2*x3) - (1/2)
f2(x1,x2,x3) = x1^2 - 81*(x2 + 0.1)^2 + sin(x3) + 1.06
f3(x1,x2,x3) = e^(-x1*x2) + 20*x3 + (10*pi - 3)/3
f = (f1,f2,f3)
j = jacobian(f, [x1,x2,x3])
I
