Haha, apologies for screwing up the review process. To continue from the
previous posts, if you first re-order the embedding to actually be clockwise,
then the trace_faces() method works as expected:
import numpy
def reorder_embedding(emb, locs):
new_emb = {}
for i,neighbors in
On Wednesday, March 26, 2014 5:34:53 PM UTC-6, Christa Brelsford wrote:
for a simple graph, trace_faces() gives the expected answer for the faces of
a planar graph, as shown below.
import networkx as nx
lat = nx.Graph()
lat.add_edge(1,2)
lat.add_edge(2,3)
lat.add_edge(2,5)
On Wednesday, March 26, 2014 5:34:53 PM UTC-6, Christa Brelsford wrote:
for a simple graph, trace_faces() gives the expected answer for the faces
of a planar graph, as shown below.
import networkx as nx
lat = nx.Graph()
lat.add_edge(1,2)
lat.add_edge(2,3)
lat.add_edge(2,5)
The problem is not in the trace_faces() method, but in the is_planar()
calculation. The embedding of the second graph is not correct:
S = Graph(lat)
S.show(vertex_size = 600, pos = nodes_dict)
S.is_planar(set_embedding = True)
s_emb = S.get_embedding()
print s_emb
{1: [2], 2: [1, 3, 5], 3: [4,
