I plotted circle using parametric equation, using circle() function.
But i want to plot x^2+y^2=4
I tried this:
var('x,y')
b=[x^2+y^2==4]
c=plot(b,(x,-2,2),(y,-2,2),color='blue')
c.save('ram.png')
I am getting the following error
TypeError: float() argument must be a string or a number
Can
You might want to use implicit_plot instead:
var('x,y')
b = x^2+y^2==4
c = implicit_plot(b,(x,-2,2),(y,-2,2),color='blue')
c.save('ram.png')
/Håkan
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You might want to use implicit_plot instead:
var('x,y')
b = x^2+y^2==4
c = implicit_plot(b,(x,-2,2),(y,-2,2),color='blue')
c.save('ram.png')
It gives the following error
TypeError: 'tuple' object is not callable
--
Priyanka Kapoor
http://kapoorpriyanka.in
Linux User Group, Ludhiana
--
On Mon, May 7, 2012 at 1:24 PM, Priyanka Kapoor
anjalicool.kapoor...@gmail.com wrote:
You might want to use implicit_plot instead:
var('x,y')
b = x^2+y^2==4
c = implicit_plot(b,(x,-2,2),(y,-2,2),color='blue')
c.save('ram.png')
It gives the following error
TypeError: 'tuple' object is not
Please note that I wrote
b = x^2+y^2==4
I got a plot.thank you. Sir , can't we draw it using plot() function.
--
Priyanka Kapoor
http://kapoorpriyanka.in
Linux User Group, Ludhiana
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