[sage-support] Re: [sage-newbie] curve length

2007-11-21 Thread William Stein
On Nov 20, 2007 7:37 PM, Mike Hansen <[EMAIL PROTECTED]> wrote: > > Hmm... I just tested it on a newer version, and I get the incorrect > answer. I'll look into it more. > It was similar to but not identical to 987 -- or more, it was that the fix for #987 wasn't sufficient. This is now fixd in

[sage-support] Re: [sage-newbie] curve length

2007-11-20 Thread Mike Hansen
Hmm... I just tested it on a newer version, and I get the incorrect answer. I'll look into it more. --Mike On Nov 20, 2007 7:03 PM, Mike Hansen <[EMAIL PROTECTED]> wrote: > This is ticket #987 which was fixed in 2.8.9. > > --Mike > > > On Nov 20, 2007 5:37 AM, David Joyner <[EMAIL PROTECTED]>

[sage-support] Re: [sage-newbie] curve length

2007-11-20 Thread Mike Hansen
This is ticket #987 which was fixed in 2.8.9. --Mike On Nov 20, 2007 5:37 AM, David Joyner <[EMAIL PROTECTED]> wrote: > > On Nov 20, 2007 8:12 AM, [EMAIL PROTECTED] > <[EMAIL PROTECTED]> wrote: > > > > As far as i know, length of curve, defined as > > f(x) > > from a to b (a <= x <= b) is > > L

[sage-support] Re: [sage-newbie] curve length

2007-11-20 Thread David Joyner
On Nov 20, 2007 8:12 AM, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote: > > As far as i know, length of curve, defined as > f(x) > from a to b (a <= x <= b) is > L = integral from a to b of sqrt(1 + df(x)^2)dx > where df(x) is diff(f,x) > > for f(x) = y = x^2 , a=0, b=2 it should be > df(x)=2x > sqr