[sage-support] Re: Derivatives of a Function?

2014-07-27 Thread Dominique Laurain
Hello Chris, seems there are two pitfalls : one when not specifying ivar parameters for desolve function call or using formal function f in the argument equation. You can try code like thisShorter code is valid too when expanding directly eq parameter (as done in SAGE help examples).. #

[sage-support] Re: Derivatives of a Function?

2014-07-26 Thread Emmanuel Charpentier
What's wrong with : sage: var(a,x) (a, x) sage: z=function(z,x) sage: f(x)=2*x+2*z*diff(z,x)/sqrt(x^2+a^2+z^2) sage: f x |-- 2*z(x)*D[0](z)(x)/sqrt(a^2 + x^2 + z(x)^2) + 2*x hmmm ? You can also write : sage: foo(x)=2*x+2*z(x)*diff(z(x),x)/sqrt(x^2+a^2+z(x)^2) sage: foo x |--