Sterling wrote:
> Now how do I evaluate f itself at those same points. I can't seem to
> figure it out.
>
f is a vector-valued function. Right now, I think the best way to
evaluate a vector-valued function is to declare it a vector:
f = vector([f1(x1,x2,x3), f2(x1,x2,x3), f3(x1,x2,x3)])
We a
Now how do I evaluate f itself at those same points. I can't seem to
figure it out.
On Sep 24, 9:47 pm, Jason Grout wrote:
> Sterling wrote:
> > How do I evaluate a Jacobian at certain values? For example, I type:
>
> > x1,x2,x3 = var('x1 x2 x3')
>
> > f1(x1,x2,x3) = 3*x1 - cos(x2*x3) - (1/2)
>
Sterling wrote:
> How do I evaluate a Jacobian at certain values? For example, I type:
>
> x1,x2,x3 = var('x1 x2 x3')
>
> f1(x1,x2,x3) = 3*x1 - cos(x2*x3) - (1/2)
> f2(x1,x2,x3) = x1^2 - 81*(x2 + 0.1)^2 + sin(x3) + 1.06
> f3(x1,x2,x3) = e^(-x1*x2) + 20*x3 + (10*pi - 3)/3
>
> f = (f1,f2,f3)
>
>
On 25 zář, 05:29, "ma...@mendelu.cz" wrote:
> On 25 zář, 04:27, Sterling wrote:
>
>
>
> > How do I evaluate a Jacobian at certain values? For example, I type:
>
> > x1,x2,x3 = var('x1 x2 x3')
>
> > f1(x1,x2,x3) = 3*x1 - cos(x2*x3) - (1/2)
> > f2(x1,x2,x3) = x1^2 - 81*(x2 + 0.1)^2 + sin(x3) + 1
On 25 zář, 04:27, Sterling wrote:
> How do I evaluate a Jacobian at certain values? For example, I type:
>
> x1,x2,x3 = var('x1 x2 x3')
>
> f1(x1,x2,x3) = 3*x1 - cos(x2*x3) - (1/2)
> f2(x1,x2,x3) = x1^2 - 81*(x2 + 0.1)^2 + sin(x3) + 1.06
> f3(x1,x2,x3) = e^(-x1*x2) + 20*x3 + (10*pi - 3)/3
>
> f
