On 2012-06-26, Chris Kees cek...@gmail.com wrote:
The following bit of code correctly computes the triple integral
(64\pi/3) for the volume of an ellipse given by 4x^2 + 4y^2 + z^2=16:
assume(0 16 - 4*x**2 - 4*y**2 16)
i1 = integral(1,0,sqrt(16 - 4*x**2 - 4*y**2))
show(i1)
assume(0 4 -
Robert,
Thanks a lot. I'll submit a bug report on the maxima bug tracker.
Chris
On Wed, Jun 27, 2012 at 10:41 AM, Robert Dodier robert.dod...@gmail.com wrote:
On 2012-06-26, Chris Kees cek...@gmail.com wrote:
The following bit of code correctly computes the triple integral
(64\pi/3) for the
