On Thursday, March 22, 2012 2:44:43 PM UTC-7, William wrote:
On Thu, Mar 22, 2012 at 5:22 PM, Kenneth A. Ribet wrote:
Consider this short sage transcript:
sage: E=EllipticCurve(GF(3),[1,1])
sage: for i in range(3):
... print i,E.order(extension_degree=i)
0 4
1 4
2 16
It's my fault as I wrote the code. if the given degree d fails the test
d1 then it's assumed to be 1 (even if d0!!). As William says, raising an
error would be better, so this should be fixed.
John
On Friday, March 23, 2012 6:08:36 PM UTC, Ken Ribet wrote:
On Thursday, March 22, 2012
Consider this short sage transcript:
sage: E=EllipticCurve(GF(3),[1,1])
sage: for i in range(3):
... print i,E.order(extension_degree=i)
0 4
1 4
2 16
Sage seem to think that E has 4 points over the field with 1 element. Was this
intended?
Ken
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On Thu, Mar 22, 2012 at 5:22 PM, Kenneth A. Ribet kri...@gmail.com wrote:
Consider this short sage transcript:
sage: E=EllipticCurve(GF(3),[1,1])
sage: for i in range(3):
... print i,E.order(extension_degree=i)
0 4
1 4
2 16
Sage seem to think that E has 4 points over the field
