Hi
thanks for your earlier answers.
I quite often do this:
sage: solve(x^3 + 10*x^2+11*x+8==0,x)
[snip]
Then I realize that the analytic solution is rather complicated.
So I want a numerical approximation.
I tried this:
roots = solve(x^3+10*x^2+11*x+8==0,x)
sage: roots
[x ==
I'm not sure if this helps your situation or not, but if you are
interested in the roots of f(x)=0, then using roots has a much more
predictable behaviour.
So for example:
sage: expr=(x^3+10*x^2+11*x+8)
sage: expr.roots()
snip
sage: expr.roots(ring=RR)
[(-8.86042628425072, 1)]
sage:
Why is evaluating this expression problematical?
y1(x)=x^2;y2(x)=5-x;
a0=1;an=3;Delta=(an-a0)/n;p(k)=a0+(k-1/2)*Delta;
I(n)=sum(abs(y2(p(k))-y1(p(k)))*Delta,k,1,n);
N(I(10))
SAGE respons:
Traceback (most recent call last):
File stdin, line 1, in module
File _sage_input_109.py, line 9, in
Hi,
On Sun, 4 Jul 2010 05:36:50 -0700 (PDT)
dirkd dirk.dancka...@gmail.com wrote:
Why is evaluating this expression problematical?
y1(x)=x^2;y2(x)=5-x;
a0=1;an=3;Delta=(an-a0)/n;p(k)=a0+(k-1/2)*Delta;
I(n)=sum(abs(y2(p(k))-y1(p(k)))*Delta,k,1,n);
N(I(10))
SAGE respons:
snip
File
Dear all,
I would like to evaluate a symbolic equation containing an integral
numerically:
((integrate(250*cos(pi*x/180)^1.8 + 170.35,x,0,18)/a_v)(a_v=1)).n()
does not work. Is there a way of doing this? The real equation is a
lot longer than the above, so I am looking for a simple automatic
