[sage-support] Re: Simplifying log expressions

2012-01-13 Thread JamesHDavenport
Unfortunately, full_simplify has its own problems, notably with branch cuts. sage: f = (1/2)*log(2*t) + (1/2)*log(-t) sage: f.full_simplify() 1/2*log(2) Unfortunately, when t=-1, we have the sum of the logarithms of two negative numbers, and therefore the imaginary part is 2i pi, not 0 On Jan 12,

Re: [sage-support] Re: Simplifying log expressions

2012-01-13 Thread Michael Orlitzky
On 01/13/2012 07:38 PM, JamesHDavenport wrote: Unfortunately, full_simplify has its own problems, notably with branch cuts. sage: f = (1/2)*log(2*t) + (1/2)*log(-t) sage: f.full_simplify() 1/2*log(2) In my session, I had the difference of two logarithms. In yours above, you've got the sum. Is