As far as I understand from your previous comments, a way to extract the
exponential functions from the expression is all you need. You don't
really need to walk through the tree. Here is one way to do this:
sage: t = exp(x+y)*(x-y)*(exp(y)+exp(z-y))
sage: t
(e^(-y + z) + e^y)*(x - y)*e^(x
On 6/24/10 6:15 AM, kcrisman wrote:
Right. This crops up in the middle of a more complicated
expression. If I could figure out how to break the expression
up in the right way, then I guess I could search for parts
that are exponential functions, take the log of those, and
then simplify the
On 06/26/2010 03:26:06 PM, Jason Grout wrote:
On 6/24/10 6:15 AM, kcrisman wrote:
Right. This crops up in the middle of a more complicated
expression. If I could figure out how to break the expression
up in the right way, then I guess I could search for parts
that are exponential functions,
I believe that Ticket #9329 was generated in response to my original
post, before I understood that there was a Latex issue involved.
I believe that Ticket #9329 should be deleted (closed or whatever).
But part of your question was also to try to simplify more complicated
expressions, and it
On 06/26/2010 05:21:21 PM, kcrisman wrote:
I believe that Ticket #9329 was generated in response to my original
post, before I understood that there was a Latex issue involved.
I believe that Ticket #9329 should be deleted (closed or whatever).
But part of your question was also to try to
Dear Mike,
Just to follow up:
There is further discussion at http://trac.sagemath.org/sage_trac/ticket/9329
if you are interested in saying exactly what sort of data structure
would enable you to perform the simplifications you would like to
without having to create a custom Maxima
On 06/25/2010 06:07:02 AM, kcrisman wrote:
Dear Mike,
Just to follow up:
There is further discussion at
http://trac.sagemath.org/sage_trac/ticket/9329
if you are interested in saying exactly what sort of data structure
would enable you to perform the simplifications you would like to
sage: n=var('n')
sage: f=e^(i*x*pi*n-i*2*pi*n)
sage: f.simplify_full()
e^(I*pi*n*x - 2*I*pi*n)
# Is there a way I can get this to simplify?
This apparently isn't even that easy in Maxima.
Maxima 5.21.1http://maxima.sourceforge.net
using Lisp ECL 10.4.1
Distributed under
On 06/24/2010 06:15:52 AM, kcrisman wrote:
sage: n=var('n')
sage: f=e^(i*x*pi*n-i*2*pi*n)
sage: f.simplify_full()
e^(I*pi*n*x - 2*I*pi*n)
# Is there a way I can get this to simplify?
This apparently isn't even that easy in Maxima.
Maxima
I've noticed too about how maxima continues to ask things that
(it would seem) you have already told it. I guess it would be
in my best interests to learn more about maxima.
If you are serious about doing symbolic manipulation that you can
control from within Sage, yes. That said, various
On 06/22/2010 12:41:17 PM, kcrisman wrote:
sage: n=var('n')
sage: f=e^(i*x*pi*n-i*2*pi*n)
sage: f.simplify_full()
e^(I*pi*n*x - 2*I*pi*n)
# Is there a way I can get this to simplify?
This apparently isn't even that easy in Maxima.
Maxima 5.21.1 http://maxima.sourceforge.net
using Lisp
sage: n=var('n')
sage: f=e^(i*x*pi*n-i*2*pi*n)
sage: f.simplify_full()
e^(I*pi*n*x - 2*I*pi*n)
# Is there a way I can get this to simplify?
This apparently isn't even that easy in Maxima.
Maxima 5.21.1 http://maxima.sourceforge.net
using Lisp ECL 10.4.1
Distributed under the GNU Public
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