Re: [SIESTA-L] K-mesh scaling for larger supercell

2009-05-19 Thread Ravi Agrawal
Hi Sophia,

As per my experience, you can reduce the k-mesh in the direction in which
you are increasing the size of your supercell. The k-mesh density, in
general, is inversely proportional to the size of the unit cell.

This means that you should be able to get the converged result for a single
gamma point calculation too, if you can manage to make your supercell large
enough.

Before following this suggestion, I would like you to wait to hear from
other experienced SIESTA users as I am also relatively new to this.

Best Regards,
Ravi


On Tue, May 19, 2009 at 10:01 AM, Sophia Nishad wrote:

> Hi Siesta users,
>
> I have a question regarding convergence of phonon calculation with respect
> to k-mesh.
>
> Suppose for an 8 atom (1x1x1x8) Si supercell Monkhrast k-mesh required is
> 16x16x16 for Gamma point phonons. If I now double the size of the supercell
> in one of the axial directions and have 16 atoms (2x1x1x8) how would the
> k-mesh be resolved for this larger supercell?
>
> To get the k-mesh denser like for the case of 8-atom supercell, we would
> need to use 8x16x16; but would it be necessary to use such equivalent dense
> mesh or due to the increase of the supercell size we can use less denser
> k-mesh, say, 8x8x4?
>
> Thanks in advance,
> --
> Sophia
>


[SIESTA-L] K-mesh scaling for larger supercell

2009-05-19 Thread Sophia Nishad
Hi Siesta users,

I have a question regarding convergence of phonon calculation with respect
to k-mesh.

Suppose for an 8 atom (1x1x1x8) Si supercell Monkhrast k-mesh required is
16x16x16 for Gamma point phonons. If I now double the size of the supercell
in one of the axial directions and have 16 atoms (2x1x1x8) how would the
k-mesh be resolved for this larger supercell?

To get the k-mesh denser like for the case of 8-atom supercell, we would
need to use 8x16x16; but would it be necessary to use such equivalent dense
mesh or due to the increase of the supercell size we can use less denser
k-mesh, say, 8x8x4?

Thanks in advance,
-- 
Sophia