> There's a win32gui.GetOpenFileName() method that provides a > lower-level interface to the open dialog. It requires you to > manually construct the Win32 API OPENFILENAME structure and > pass it in as a string, and I haven't had time to figure out > how to do that yet.
There's an example here: <http://mail.python.org/pipermail/pythonce/2002-October/000204.html> It's for Windows CE, I think, but is probably more-or-less the same :) =Tony.Meyer _______________________________________________ spambayes-dev mailing list spambayes-dev@python.org http://mail.python.org/mailman/listinfo/spambayes-dev
