[sqlalchemy] Re: JOIN result as dict
q.all()._asdict()
It does not work. It is a kind of a mental shortcut (sorry for that!). It
is only possible in (like you said):
for r in q.all():
r._as_dict()
Thank you for your reply! I had hope that I don't have to do any casting or
explicity query enumerate.
W dniu czwartek, 20 października 2016 19:11:56 UTC+2 użytkownik Jonathan
Vanasco napisał:
>
> I'm sorry, I totally misunderstood your question. I thought you were
> trying to get all rows as a unified dict. Your result clarified things.
>
> It looks like you're using the ORM (and not core), right?
>
> I don't think it is entirely possible to do what you want. Several people
> have asked similar questions in the past... you essentially want
> SqlAlchemy to return somewhat raw data.
>
> The problem isn't with the `join`, it's with the `query`.
>
> This bit:
>
> query(table1.t1c2, table2)
>
> Is instructing SqlAlchemy to return a tuple that contains those two
> discrete "objects" - the first being a column of `table1`, the second being
> a instance of `table2` (or a row). The ORM is then mapping table2 onto an
> object.
>
> To *somewhat* achieve your goal and avoid the object creation, you can
> explicitly enumerate your query:
>
> r = db.session.query(Table1.t1c2, Table2.t2c1, Table2.t2c2,
> Table2.t2c3).join(Table2).all()
>
> That will return an iterator of 3 element tuples in that order:
>
> [(u'one', 11, u'qwe', 1),
> (u'two', 22, u'rty', 2),
> (u'one', 33, u'zxcvb', 1)
> ]
>
> You can cast each one into a dict individually:
>
> for row in r:
>print row._as_dict()
>
> will generate:
>
> {'t1c2': u'one', 't2c3': 1, 't2c2': u'qwe', 't2c1': 11}
> {'t1c2': u'two', 't2c3': 2, 't2c2': u'rty', 't2c1': 22}
> {'t1c2': u'one', 't2c3': 1, 't2c2': u'zxcvb', 't2c1': 33}
>
> That brings me to this point -- can you share a self-contained example of
> your code?
>
> I can't figure out how you're getting `q.all()._asdict()` to work. It
> shouldn't work, because the result should be an iterable/list that does not
> have that method.
>
>
--
SQLAlchemy -
The Python SQL Toolkit and Object Relational Mapper
http://www.sqlalchemy.org/
To post example code, please provide an MCVE: Minimal, Complete, and Verifiable
Example. See http://stackoverflow.com/help/mcve for a full description.
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[sqlalchemy] Re: JOIN result as dict
I'm sorry, I totally misunderstood your question. I thought you were trying
to get all rows as a unified dict. Your result clarified things.
It looks like you're using the ORM (and not core), right?
I don't think it is entirely possible to do what you want. Several people
have asked similar questions in the past... you essentially want
SqlAlchemy to return somewhat raw data.
The problem isn't with the `join`, it's with the `query`.
This bit:
query(table1.t1c2, table2)
Is instructing SqlAlchemy to return a tuple that contains those two
discrete "objects" - the first being a column of `table1`, the second being
a instance of `table2` (or a row). The ORM is then mapping table2 onto an
object.
To *somewhat* achieve your goal and avoid the object creation, you can
explicitly enumerate your query:
r = db.session.query(Table1.t1c2, Table2.t2c1, Table2.t2c2,
Table2.t2c3).join(Table2).all()
That will return an iterator of 3 element tuples in that order:
[(u'one', 11, u'qwe', 1),
(u'two', 22, u'rty', 2),
(u'one', 33, u'zxcvb', 1)
]
You can cast each one into a dict individually:
for row in r:
print row._as_dict()
will generate:
{'t1c2': u'one', 't2c3': 1, 't2c2': u'qwe', 't2c1': 11}
{'t1c2': u'two', 't2c3': 2, 't2c2': u'rty', 't2c1': 22}
{'t1c2': u'one', 't2c3': 1, 't2c2': u'zxcvb', 't2c1': 33}
That brings me to this point -- can you share a self-contained example of
your code?
I can't figure out how you're getting `q.all()._asdict()` to work. It
shouldn't work, because the result should be an iterable/list that does not
have that method.
--
SQLAlchemy -
The Python SQL Toolkit and Object Relational Mapper
http://www.sqlalchemy.org/
To post example code, please provide an MCVE: Minimal, Complete, and Verifiable
Example. See http://stackoverflow.com/help/mcve for a full description.
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[sqlalchemy] Re: JOIN result as dict
q.all() returns me a result in format:
[('one', {'t2c2': 'qwe',
't2c1': '11',
't2c3': '1'}),
('two', {'t2c2': 'rty',
't2c1': '22',
't2c3': '2'}),
..]
The result of
q.all()._asdict()
is
[{
't1c2': 'one',
'table2': {
't2c2': 'qwe',
't2c1': '11',
't2c3': '1'
}
},
{
't1c2': 'two',
'table2': {
't2c2': 'rty',
't2c1': '22',
't2c3': '2'
}
},
...]
Above solutions aren't result whose I excepted.
I try to avoid any casting in Python.
Is it possible?
W dniu poniedziałek, 17 października 2016 18:52:59 UTC+2 użytkownik
Jonathan Vanasco napisał:
>
> Your query's underlying sql returns multiple rows. You can cast those
> results into a dict in Python.
>
>
>
--
SQLAlchemy -
The Python SQL Toolkit and Object Relational Mapper
http://www.sqlalchemy.org/
To post example code, please provide an MCVE: Minimal, Complete, and Verifiable
Example. See http://stackoverflow.com/help/mcve for a full description.
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[sqlalchemy] Re: JOIN result as dict
Your query's underlying sql returns multiple rows. You can cast those results into a dict in Python. -- SQLAlchemy - The Python SQL Toolkit and Object Relational Mapper http://www.sqlalchemy.org/ To post example code, please provide an MCVE: Minimal, Complete, and Verifiable Example. See http://stackoverflow.com/help/mcve for a full description. --- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sqlalchemy+unsubscr...@googlegroups.com. To post to this group, send email to sqlalchemy@googlegroups.com. Visit this group at https://groups.google.com/group/sqlalchemy. For more options, visit https://groups.google.com/d/optout.
