This will work great - just a correction, there should be a comma after
"columnB" in the order by clause, else it might not parse, so the
revised is:
SELECT * FROM table
ORDER BY columnA, columnB,
CASE WHEN columnC = 1
THEN 0 ELSE 1 END;
On 2015-08-22 10:47 PM,
afriendandmore wrote:
> The table shall be ordered according to A. (Order by A)
> But if C ist true and to the value B1 in this Record, there exists another
> Record with B2 and B2 = B1, then B1 should be ordered in the row above B2.
Do those two records have the same A values?
Regards,
On Sat, Aug 22, 2015
> afriendandmore wrote:
> > The table shall be ordered according to A. (Order by A)
> > But if C ist true and to the value B1 in this Record, there exists
> another Record with B2 and B2 = B1, then B1 should be ordered in the row
> above B2.
If the B1 and B2, to which you
but I fail to get it done.
Hello,
I got the following problem, that I cannot get worked out.
I have a table that has 3 columns A, B and C.
C is a boolean Column, that indicates if the record has been logically
deleted, It shall not be removed from the database.
The table shall be ordered
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