On 06/30/2011 10:31 AM, Ryan Henrie wrote:
> Reference Page: http://www.sqlite.org/fts3.html#appendix_a
>
> At the bottom of the page, there is a sample c file to calculate the
> rank, and a FTS query to use it. I can't get it to work.
>
> You can see my files here:
>
> http://coldmist.homeip.net/
Reference Page: http://www.sqlite.org/fts3.html#appendix_a
At the bottom of the page, there is a sample c file to calculate the
rank, and a FTS query to use it. I can't get it to work.
You can see my files here:
http://coldmist.homeip.net/quotes_sql_test.txt
http://coldmist.homeip.net/rank.c.t
On 6/29/2011 12:53 PM, Pete wrote:
> Looking for opinions on the relative efiiciency of Scalar queries versus
> non-scalar with JOIN statements.
>
> For example, the following two queries would produce the same results but
> would one of them be significantly faster than the other?
>
> SELECT colum
Looking for opinions on the relative efiiciency of Scalar queries versus
non-scalar with JOIN statements.
For example, the following two queries would produce the same results but
would one of them be significantly faster than the other?
SELECT column1, tableB.column2 FROM TableA LEFT JOIN TableB
On 30/06/2011, at 12:35 AM, Ian Hardingham wrote:
> I have an existing table, the matchTable, where each entry holds a lot
> of information about a "match".
>
> I am adding a tournament system, and each match will either be in a
> tournament or not in a tournament.
>
> Should I add a "tourname
On Jun 29, 2011, at 10:35 AM, Ian Hardingham wrote:
> Hey guys.
>
> I have an existing table, the matchTable, where each entry holds a lot
> of information about a "match".
>
> I am adding a tournament system, and each match will either be in a
> tournament or not in a tournament.
>
> Should
Hey guys.
I have an existing table, the matchTable, where each entry holds a lot
of information about a "match".
I am adding a tournament system, and each match will either be in a
tournament or not in a tournament.
Should I add a "tournamentID" column to matchTable? Or should I create
a new
Good idea.
The result was : ok
Of note, we found in our dump and import duplicate 4 entries that violated
uniqueness of the primary key. (2 entries of 4 different primary keys, with
only 1 other field having a different int.) We identified which one belongs
and commented out the others. How did
On 29 Jun 2011, at 2:27pm, profove wrote:
> There were about two hundred thousand of insert statements, but it
> executed too slow.
Before the first INSERT statement insert a command 'BEGIN;'.
After the last INSERT statement insert a command 'COMMIT;'.
Simon.
___
.read FILENAME Execute SQL in FILENAME
When I want to restore a database. I execute a command in sqlite3 with
".read file" then execute my sql statements in the named file.
There were about two hundred thousand of insert statements, but it
executed too slow.
I checked the source code and it will
On 29 Jun 2011, at 2:04pm, Adam DeVita wrote:
> On Tue, Jun 28, 2011 at 11:34 AM, Simon Slavin wrote:
>
>> Use the sqlite3 command-line shell to dump the database to SQL commands,
>> then create a new database by reading it back in.
>>
>> While the data is in the SQL command file, you can take
Success!
On Tue, Jun 28, 2011 at 11:34 AM, Simon Slavin wrote:
>
> On 28 Jun 2011, at 4:22pm, Adam DeVita wrote:
>
> > I can see the data that I want to export. How do I fix these indexes?
>
> Use the sqlite3 command-line shell to dump the database to SQL commands,
> then create a new databa
Well I checked the source code and there is no xml comments for any of the
exceptions. This explains why they don't show up in the chm help file or in
Intellisense. I've requested that the documentation be added (or offered to do
it for them). We'll see what happens.
-Jay-
-Original Mess
On Wed, 29 Jun 2011 13:21:21 +0200, Roger Andersson
wrote:
>:) No CAST needed
>SELECT round((COUNT(rowid))/(SELECT COUNT(*)*0.01 FROM people),2) FROM
>people WHERE zip="12345";
Thanks everyone.
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On 06/29/11 01:01 PM, Cecil Westerhof wrote:
> 2011/6/29 Roger Andersson mailto:r...@telia.com>>
>
> SELECT round(cast(COUNT(rowid)*100 as real)/(SELECT COUNT(*) FROM
> people),2) FROM people WHERE zip="12345";
>
>
> Would it not be better to do the CAST on the second SELECT? Then there
On 06/29/11 01:02 PM, Mr. Puneet Kishor wrote:
> SELECT (COUNT(rowid)*100)/(SELECT COUNT(*) FROM people) * 1.00 AS percentage
> FROM people
> WHERE zip="12345";
Seems to always return .0 ?
/Roger
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On Jun 29, 2011, at 6:53 AM, Roger Andersson wrote:
> On 06/29/11 12:34 PM, Gilles Ganault wrote:
>> Thanks, that worked:
>> SELECT COUNT(*) FROM people;
>> 400599
>>
>> SELECT COUNT(*) FROM people WHERE zip="12345";
>> 12521
>>
>> SELECT (COUNT(rowid)*100)/(SELECT COUNT(*) FROM people) FROM p
2011/6/29 Roger Andersson
> SELECT round(cast(COUNT(rowid)*100 as real)/(SELECT COUNT(*) FROM
> people),2) FROM people WHERE zip="12345";
>
Would it not be better to do the CAST on the second SELECT? Then there is
only one CAST needed. In this case it does not matter much, but in the
general cas
On 06/29/11 12:34 PM, Gilles Ganault wrote:
> Thanks, that worked:
> SELECT COUNT(*) FROM people;
> 400599
>
> SELECT COUNT(*) FROM people WHERE zip="12345";
> 12521
>
> SELECT (COUNT(rowid)*100)/(SELECT COUNT(*) FROM people) FROM people
> WHERE zip="12345";
> 3
>
> Is it possible to display the
On 29 June 2011 11:34, Gilles Ganault wrote:
> On Wed, 29 Jun 2011 11:33:15 +0200, Roger Andersson
> wrote:
>>SELECT (COUNT(rowid)*100)/(select count(*) from people) FROM people WHERE
>>zip="12345";
>
> Thanks, that worked:
>
> SELECT COUNT(*) FROM people;
> 400599
>
> SELECT COUNT(*) FROM peopl
On Wed, 29 Jun 2011 11:33:15 +0200, Roger Andersson
wrote:
>SELECT (COUNT(rowid)*100)/(select count(*) from people) FROM people WHERE
>zip="12345";
Thanks, that worked:
SELECT COUNT(*) FROM people;
400599
SELECT COUNT(*) FROM people WHERE zip="12345";
12521
SELECT (COUNT(rowid)*100)/(SELECT C
Oliver Peters writes:
I definitely need glasses for my glasses
AS cnt_all_people belongs after COUNT(zip)
so this is correct
SELECT a.zip, a.cnt_people_in_town, b.cnt_all_people
(
SELECT zip, COUNT(zip) AS cnt_people_in_town
FROM people
GROUP BY zip
) a
CROSS JOIN
(
SELECT COUNT(zip) AS cnt_
Gilles Ganault writes:
SELECT a.zip, a.cnt_people_in_town, b.cnt_all_people
(
SELECT zip, COUNT(zip) AS cnt_people_in_town
FROM people
GROUP BY zip
) a
CROSS JOIN
(
SELECT COUNT(zip)
FROM people AS cnt_all_people
) b
;
percent for you
greetings
oliver
___
On 06/29/11 11:22 AM, Gilles Ganault wrote:
> Hello
>
> Using a table that lists people and the zipcode where they live, I
> need to compute the percentage of those living in, say, NYC.
>
> I googled for this, but I'm not sure how to do this in SQLite.
>
> I wonder if it's done through a su
Hello
Using a table that lists people and the zipcode where they live, I
need to compute the percentage of those living in, say, NYC.
I googled for this, but I'm not sure how to do this in SQLite.
I wonder if it's done through a sub-query or maybe some temporary
variable?
This computes
Test.
--
Joe Mistachkin
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