The answer to you exact question is "Yes". Didn't help much did it?
But I will at least start off by giving some hints. You need to do an inner
join on the common column (service_no). You need to use the HAVING clause
to select only those entries with more than 2 entries in the result table
There are 2 related table above. There are service_no 1,2,3,5. Service 1,2,3
are type e-line, service 5 is type e-lan. Service 1,2,3 own 2
service_port(sp_no 1,2). Service 5 owns 3 service_port(sp_no 1,2,3).
What is the count of services have more than 2 service_port(sp) and type is
e-lan?
On 9/3/2013 6:52 PM, ChingChang Hsiao wrote:
What is the count of services have more than 2 service_port(sp) and type is
e-lan? The answer is 1. Could it be described as one sql statement?
select count(*) from service_table s
where service_type = 'e-lan' and
(select count(*) from
CREATE TABLE service_table (
service_nameTEXT, /* name of the service (unique) */
service_no INTEGER, /* internal service number, assigned by the
system. */
service_typeTEXT, /* Type of Service. Should be one of
CREATE TABLE service_table (
service_nameTEXT, /* name of the service (unique) */
service_no INTEGER, /* internal service number, assigned by the
system. */
service_typeTEXT, /* Type of Service. Should be one of
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