Re: [sqlite] how to write sql cmd for this situation:

2012-10-08 Thread Igor Tandetnik
YAN HONG YE wrote: > I have a 2 table: > 1. tb1: > > aa bb cc mdate > 1 d1 2.5 2012-08-07 > 2 d2 3.3 2012-08-07 > 3 d1 6.4 2012-08-09 > > 2. tb2: > aa bb cc > 1. d1 5.3 > 2. d2 7.6 > > mysql sql cmd is: > > select tb2.bb,tb2.cc,(max(tb1.mdate)-min(tb1.mdate))

Re: [sqlite] how to write sql cmd for this situation

2012-10-08 Thread YAN HONG YE
"Igor Tandetnik" reply: YAN HONG YE wrote: > mysql sql cmd is: > > select tb2.bb,tb2.cc,(max(tb1.mdate)-min(tb1.mdate)) as mmd,(mmd. > max(tb1.mdate).cc-mmd. min(tb1.mdate).cc) as mmc from tb1,tb2 > where tb2.bb in (select bb from tb1 where bb group

Re: [sqlite] how to write sql cmd for this situation:

2012-10-07 Thread Igor Tandetnik
YAN HONG YE wrote: > mysql sql cmd is: > > select tb2.bb,tb2.cc,(max(tb1.mdate)-min(tb1.mdate)) as mmd,(mmd. > max(tb1.mdate).cc-mmd. min(tb1.mdate).cc) as mmc from tb1,tb2 > where tb2.bb in (select bb from tb1 where bb group by bb having count(bb)) ; With all due

[sqlite] how to write sql cmd for this situation:

2012-10-07 Thread YAN HONG YE
I have a 2 table: 1. tb1: aa bb cc mdate 1 d1 2.5 2012-08-07 2 d2 3.3 2012-08-07 3 d1 6.4 2012-08-09 2. tb2: aa bb cc 1. d1 5.3 2. d2 7.6 mysql sql cmd is: select tb2.bb,tb2.cc,(max(tb1.mdate)-min(tb1.mdate)) as mmd,(mmd. max(tb1.mdate).cc-mmd. min(tb1.mdate).cc) as mmc from