Le 2012-07-10 08:53, Garth Paine a écrit :
So I guess as you suggest I could use one instance of Harpex for my main
horizontal layout and then another instance with 2 or more shotguns
raised in elevation to manage the height, depending on the available
speakers
Certainly worth a try!
- Daniel
...@linuxaudio.org
To: sursound@music.vt.edu
Sent: Mon, July 9, 2012 6:48:40 AM
Subject: Re: [Sursound] higher order ambisonics over 8 to 10 loudspeakers
On Mon, Jul 09, 2012 at 11:13:04PM +1000, GP wrote:
If the min is (N+1)².
Surely for 3rd order that is
(3+1)² = 16 speakers?
The minimum is (M + 1)^2
On 07/09/2012 03:17 PM, GP wrote:
I did wonder about using Daniel Courville's plugins to do decoding
for the height info separate to HARPEX. The HARPEX decoding does
sound good ( how can I confirm it is 3rd order over 8 speakers?) and
so if I could add height using another approach that would be
ahh thanks Daniel I had not seen that. Would be cool if the speaker layout GUI
could be rotated so one could see the 3D layout more clearly. So I guess as
you suggest I could use one instance of Harpex for my main horizontal layout
and then another instance with 2 or more shotguns raised in
Hi everyone
I have been gathering lots of ambient field recordings in A-Format for a few
years using my SPS200 Soundfiled mike and a 788T. I have experimented with
playback over an 8 channel circle, and also with 3 circles of 8 at different
heights (roof, 3M, 1M), and some other arrangements.
On 07/09/2012 01:17 PM, Garth Paine wrote:
Hi everyone
I have been gathering lots of ambient field recordings in A-Format
for a few years using my SPS200 Soundfiled mike and a 788T. I have
experimented with playback over an 8 channel circle, and also with 3
circles of 8 at different heights
I cant remember the formula off hand but it important ,I am told, to use
the correct number of speakers for the order you are using - so if you use
too many speakers for the order that can also muddy up the localisation.
Someone will enlighten us Im sure but is it :
the order number + 1 squared
that is for 3d by the way but not sure ... anyone ?
On 9 July 2012 12:31, Augustine Leudar augustineleu...@gmail.com wrote:
I cant remember the formula off hand but it important ,I am told, to use
the correct number of speakers for the order you are using - so if you use
too many
Thanks for that feedback - I have HARPEX, but did not realise it does
third-order horizontal? One drawback with Harpex is it does not do height
Cheers
Garth
http://www.activatedspace.com
http://www.syncsonics.com
On 09/07/2012, at 9:27 PM, Jörn Nettingsmeier wrote:
On 07/09/2012 01:17
On 07/09/2012 01:57 PM, Garth Paine wrote:
Thanks for that feedback - I have HARPEX, but did not realise it does
third-order horizontal? One drawback with Harpex is it does not do height
you could do HARPEX on the 8 horizontal speakers, then take two virtual
microphones, aim them into the
On 07/09/2012 01:32 PM, Augustine Leudar wrote:
that is for 3d by the way but not sure ... anyone ?
there are no hard upper limits. the absolute lower limit is (N+1)².
in horizontal layouts, i find 8 too much for first order, and 12 too
much for third order. the issue is that additional
On Mon, Jul 09, 2012 at 11:13:04PM +1000, GP wrote:
If the min is (N+1)².
Surely for 3rd order that is
(3+1)² = 16 speakers?
The minimum is (M + 1)^2 for 3D, and (2 * M) + 1 for 2D, but
- You better use at least on more,
- For 3D, the minimum is 8, even for first order. That is because
wishes,
--Richard
-Original Message-
From: sursound-boun...@music.vt.edu [mailto:sursound-boun...@music.vt.edu]
On Behalf Of Augustine Leudar
Sent: 09 July 2012 12:32
To: Surround Sound discussion group
Subject: Re: [Sursound] higher order ambisonics over 8 to 10 loudspeakers
I cant remember
Le 2012-07-09 09:17, GP a écrit :
I did wonder about using Daniel Courville's plugins to do decoding for
the height info separate to HARPEX. The HARPEX decoding does sound good (
how can I confirm it is 3rd order over 8 speakers?) and so if I could add
height using another approach that would be
:40 AM
Subject: Re: [Sursound] higher order ambisonics over 8 to 10 loudspeakers
On Mon, Jul 09, 2012 at 11:13:04PM +1000, GP wrote:
If the min is (N+1)².
Surely for 3rd order that is
(3+1)² = 16 speakers?
The minimum is (M + 1)^2 for 3D, and (2 * M) + 1 for 2D, but
- You better use
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