Re: [Biofuel] Better titration Question

2006-01-03 Thread John Hayes
Ken Provost wrote:
 On Jan 2, 2006, at 3:33 PM, Logan Vilas wrote:
 
 In the better Titration Method I find it's easier to mix my stock  
 solution
 with 20grams in 500milliters distilled water.
 
 
 OK -- we now have 4% NaOH soln.
 
 
 That gives .4% w/v lye solution when 5ml is added to 45ml distilled  
 water.
 
 
 Yes, if you add 5ml of your 4% soln. to 45ml of water, you get a
 0.4% solution. This is still 4 times the concentration that everyone
 else uses.
 
 
 By doing this I do not have to divide the titration results.
 
 
 I don't understand what you mean by this. When using a 0.1% soln.,
 the number of milliliters of soln. needed to neutralize 1ml of oil is
 equal to the number of grams NaOH which must be added to the
 usual 3.5g per liter of oil. With your 4X solution, you will achieve
 neutrality at only 1/4 as many milliliters of solution, and thus will
 need to multiply by four to calculate the proper excess of NaOH.
 
 
 I haven't had any problems yet, but I was wondering if anyone
 would know of a reason I shouldn't do it?
 
 
 As long as you make the proper multiplication by four, your solution
 will work fine.
 
 
 Or if there is anyone using this method?
 
 
 I can't see why anyone would.
 
 
 -K

Then you seem to have a short memory Ken. Didn't we discuss doing 
exactly this back in April?

http://www.mail-archive.com/biofuel@sustainablelists.org/msg45657.html

There is a very good reason to use a 0.4% (w/v) titration solution with 
4mL of WVO - namely accuracy.

By using 4mL of WVO in some volume of isopropanol with 0.4% (w/v) base, 
you still get a direct relationship between number of mL of base 
required in the titration and number of grams of lye required per liter 
for the reaction *AND* you get a more accurate measurement, *without* 
needing to do any calculations on the bench.

Anyway, Logan, to answer your question, yes, some of us (ok, maybe just 
me) are in fact using a 0.4% (w/v) NaOH titration solution.

jh




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Re: [Biofuel] Better titration Question

2006-01-03 Thread bob allen
It seems to me that using a more concentrated titrant would increase error not 
reduce it.  Better 
would be to use more of a less concentrated titrant with a higher volume of the 
solution to be 
titrated (other things being equal)

John Hayes wrote:
 Ken Provost wrote:
 
On Jan 2, 2006, at 3:33 PM, Logan Vilas wrote:


In the better Titration Method I find it's easier to mix my stock  
solution
with 20grams in 500milliters distilled water.


OK -- we now have 4% NaOH soln.



That gives .4% w/v lye solution when 5ml is added to 45ml distilled  
water.


Yes, if you add 5ml of your 4% soln. to 45ml of water, you get a
0.4% solution. This is still 4 times the concentration that everyone
else uses.



By doing this I do not have to divide the titration results.


I don't understand what you mean by this. When using a 0.1% soln.,
the number of milliliters of soln. needed to neutralize 1ml of oil is
equal to the number of grams NaOH which must be added to the
usual 3.5g per liter of oil. With your 4X solution, you will achieve
neutrality at only 1/4 as many milliliters of solution, and thus will
need to multiply by four to calculate the proper excess of NaOH.



I haven't had any problems yet, but I was wondering if anyone
would know of a reason I shouldn't do it?


As long as you make the proper multiplication by four, your solution
will work fine.



Or if there is anyone using this method?


I can't see why anyone would.


-K
 
 
 Then you seem to have a short memory Ken. Didn't we discuss doing 
 exactly this back in April?
 
 http://www.mail-archive.com/biofuel@sustainablelists.org/msg45657.html
 
 There is a very good reason to use a 0.4% (w/v) titration solution with 
 4mL of WVO - namely accuracy.
 
 By using 4mL of WVO in some volume of isopropanol with 0.4% (w/v) base, 
 you still get a direct relationship between number of mL of base 
 required in the titration and number of grams of lye required per liter 
 for the reaction *AND* you get a more accurate measurement, *without* 
 needing to do any calculations on the bench.
 
 Anyway, Logan, to answer your question, yes, some of us (ok, maybe just 
 me) are in fact using a 0.4% (w/v) NaOH titration solution.
 
 jh
 
 
 
 
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 http://www.mail-archive.com/biofuel@sustainablelists.org/
 
 
 
 
 


-- 
Bob Allen
http://ozarker.org/bob

Science is what we have learned about how to keep
from fooling ourselves - Richard Feynman

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Re: [Biofuel] Better titration Question

2006-01-03 Thread Ken Provost

On Jan 2, 2006, at 8:20 PM, Logan Vilas wrote:



 When using the better titration method I'm using 4ml oil and 40ml  
 Isopropyl.


Ah,ha!  Well, I guess I should have read what the better titration
method  involved! Not sure why it's better, but clearly it will work.

-K

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[Biofuel] Better titration Question

2006-01-02 Thread Logan Vilas
In the better Titration Method I find it's easier to mix my stock solution
with 20grams in 500milliters distilled water. That gives .4% w/v lye
solution when 5ml is added to 45ml distilled water. By doing this I do not
have to divide the titration results. I haven't had any problems yet, but I
was wondering if anyone would know of a reason I shouldn't do it? Or if
there is anyone using this method?

Logan Vilas


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Re: [Biofuel] Better titration Question

2006-01-02 Thread Ken Provost

On Jan 2, 2006, at 3:33 PM, Logan Vilas wrote:

 In the better Titration Method I find it's easier to mix my stock  
 solution
 with 20grams in 500milliters distilled water.


OK -- we now have 4% NaOH soln.


 That gives .4% w/v lye solution when 5ml is added to 45ml distilled  
 water.


Yes, if you add 5ml of your 4% soln. to 45ml of water, you get a
0.4% solution. This is still 4 times the concentration that everyone
else uses.


 By doing this I do not have to divide the titration results.


I don't understand what you mean by this. When using a 0.1% soln.,
the number of milliliters of soln. needed to neutralize 1ml of oil is
equal to the number of grams NaOH which must be added to the
usual 3.5g per liter of oil. With your 4X solution, you will achieve
neutrality at only 1/4 as many milliliters of solution, and thus will
need to multiply by four to calculate the proper excess of NaOH.


 I haven't had any problems yet, but I was wondering if anyone
 would know of a reason I shouldn't do it?


As long as you make the proper multiplication by four, your solution
will work fine.


 Or if there is anyone using this method?


I can't see why anyone would.


-K

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Re: [Biofuel] Better titration Question

2006-01-02 Thread Logan Vilas
Ken

When using the better titration method I'm using 4ml oil and 40ml Isopropyl.


As per the method on JTF you do that then divide by 4. I am just multiplying
the lye solution by 4 before doing the titration to remove the step of
dividing in the end.

I should have said the proportions of my titration ahead of time.

Logan Vilas


-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Ken Provost
Sent: Monday, January 02, 2006 9:10 PM
To: Biofuel@sustainablelists.org
Subject: Re: [Biofuel] Better titration Question


On Jan 2, 2006, at 3:33 PM, Logan Vilas wrote:

 In the better Titration Method I find it's easier to mix my stock  
 solution
 with 20grams in 500milliters distilled water.


OK -- we now have 4% NaOH soln.


 That gives .4% w/v lye solution when 5ml is added to 45ml distilled  
 water.


Yes, if you add 5ml of your 4% soln. to 45ml of water, you get a
0.4% solution. This is still 4 times the concentration that everyone
else uses.


 By doing this I do not have to divide the titration results.


I don't understand what you mean by this. When using a 0.1% soln.,
the number of milliliters of soln. needed to neutralize 1ml of oil is
equal to the number of grams NaOH which must be added to the
usual 3.5g per liter of oil. With your 4X solution, you will achieve
neutrality at only 1/4 as many milliliters of solution, and thus will
need to multiply by four to calculate the proper excess of NaOH.


 I haven't had any problems yet, but I was wondering if anyone
 would know of a reason I shouldn't do it?


As long as you make the proper multiplication by four, your solution
will work fine.


 Or if there is anyone using this method?


I can't see why anyone would.


-K



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