> It is just like there were two ways to do the job, you thought it worked
in this way, but it chose the other way. Both ways lead to the same result.
I think it is because the compiler **flatten** your inner function instead
of calculated the result.
The variable scope of `closure` is outside th
It seems to me you are shooting while blindfolded.
> I changed you code `let result = closure(n)` to `let result = closure(1)`. I
> thought that should eliminate the error. It didn't. The compiler asked me to
> change the whole code as below:
Why did you expect changing which argument to send
