Typo, should be instance not istance.
--
Adrian Zubarev
Sent with Airmail
Am 18. Februar 2017 um 12:16:34, Adrian Zubarev
(adrian.zuba...@devandartist.com) schrieb:
You’re welcome. I don’t think there is a better way of doing that. However you
can build some wrappers with some shortcuts.
f
You’re welcome. I don’t think there is a better way of doing that. However you
can build some wrappers with some shortcuts.
func createInstance(of _: T.Type, _ istance: T) -> T {
return istance
}
let myGreatFunc1 = createInstance(of: Function.self) {
return "\($0) \($1)" // O
Just tried it, unfortunately it does not achieve what I wanted. As soon as a
parameter is added, the compiler complains (rightly so) about ignoring an
argument.
Oh well, at least I get warnings when parameters are added so that I don’t have
to remember which functions need a touch-up.
Regards
It feels a bit strange to write it like that, but yes, that would work. Thanks!
(It will prevent me from having to touch up old functions when adding more
parameters to the signature as the project evolves)
Regards,
Rien
Site: http://balancingrock.nl
Blog: http://swiftrien.blogspot.com
Github:
Sorry: “prevent me from” should have been “allow me to avoid”
Regards,
Rien
Site: http://balancingrock.nl
Blog: http://swiftrien.blogspot.com
Github: http://github.com/Balancingrock
Project: http://swiftfire.nl
> On 18 Feb 2017, at 12:05, Rien wrote:
>
> It feels a bit strange to write it
Not sure what you’re trying to solve there but you could use it like this with
closures:
typealias Function = (Int, Bool) -> String?
let myGreatFunc1: Function = { _ in return nil /* or whatever you need there */
}
let myGreatFunc2: Function = { _ in return nil }
--
Adrian Zubarev
Sent with
I want to create a few functions that all have the same signature.
The signature is defined in a typealias
Is there any way to shortcut the function definition, or alternatively ensure
that the function signature will always be equal to the typealias?
Examplecode:
typealias Mysig = (Int, Bool)