Re: [swift-users] How to resolve "type(of: instance)" being shadowed by "instance.type"?

[Glen Huang via swift-users]

Ah, how come I never thought about trying that!?

Thanks!

Regards,
Glen

> On 23 Sep 2017, at 1:10 PM, Slava Pestov  wrote:
> 
> 
>> On Sep 22, 2017, at 10:10 PM, Glen Huang via swift-users 
>>  wrote:
>> 
>> I have a class like this:
>> 
>> class File {
>>  type: FileType
>>  url: URL
>>  func fetch(from server: Server) {
>>  type(of: server).get(from: url)
>>  }
>> }
>> 
>> However, it fails to compile with "Cannot call value of non-function type 
>> ‘File’” inside the body of fetch(from:). I believe the reason is that 
>> self.type shadows  type(of: server).
>> 
>> Other than renaming the “type” property, is there any other way to work 
>> around it? I tried "Foundation.type(of: server)” and found out that it’s 
>> from the standard library and not Foundation. Is there a prefix that denotes 
>> the standard library?
> 
> The standard library module is named ‘Swift’, so ‘Swift.type(of:)’ should do 
> the trick.
> 
>> 
>> A more general question, since this is clearly a function call, why would it 
>> be shadowed by self.type, which is clearly a property access?
>> 
>> I’m using Swift 4 in Xcode 9.
>> 
>> Regards,
>> Glen
>> ___
>> swift-users mailing list
>> swift-users@swift.org
>> https://lists.swift.org/mailman/listinfo/swift-users
> 

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Re: [swift-users] How to resolve "type(of: instance)" being shadowed by "instance.type"?

[Slava Pestov via swift-users]

> On Sep 22, 2017, at 10:10 PM, Glen Huang via swift-users 
>  wrote:
> 
> I have a class like this:
> 
> class File {
>   type: FileType
>   url: URL
>   func fetch(from server: Server) {
>   type(of: server).get(from: url)
>   }
> }
> 
> However, it fails to compile with "Cannot call value of non-function type 
> ‘File’” inside the body of fetch(from:). I believe the reason is that 
> self.type shadows  type(of: server).
> 
> Other than renaming the “type” property, is there any other way to work 
> around it? I tried "Foundation.type(of: server)” and found out that it’s from 
> the standard library and not Foundation. Is there a prefix that denotes the 
> standard library?

The standard library module is named ‘Swift’, so ‘Swift.type(of:)’ should do 
the trick.

> 
> A more general question, since this is clearly a function call, why would it 
> be shadowed by self.type, which is clearly a property access?
> 
> I’m using Swift 4 in Xcode 9.
> 
> Regards,
> Glen
> ___
> swift-users mailing list
> swift-users@swift.org
> https://lists.swift.org/mailman/listinfo/swift-users

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[swift-users] How to resolve "type(of: instance)" being shadowed by "instance.type"?

[Glen Huang via swift-users]

I have a class like this:

class File {
   type: FileType
   url: URL
   func fetch(from server: Server) {
   type(of: server).get(from: url)
   }
}

However, it fails to compile with "Cannot call value of non-function type 
‘File’” inside the body of fetch(from:). I believe the reason is that self.type 
shadows  type(of: server).

Other than renaming the “type” property, is there any other way to work around 
it? I tried "Foundation.type(of: server)” and found out that it’s from the 
standard library and not Foundation. Is there a prefix that denotes the 
standard library?

A more general question, since this is clearly a function call, why would it be 
shadowed by self.type, which is clearly a property access?

I’m using Swift 4 in Xcode 9.

Regards,
Glen
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