In your example, when `Foo` is a class, then `A` does not see a mutation since
the storage is out-of-line. When `Foo` is a struct, it is stored in-line and a
mutation does mutate `A`.
In other words, when what’s stored in `A` is a reference, the reference itself
does not get mutated when you mu
> My code depends on the class version didSet but I used the struct version. It
> took me a long time to debug this out. Is this a knowledge that has been well
> known already?
Yes, that’s how it’s supposed to be.
It’s a feature of struct which isn’t available with classes (so considering the
O
Hi everyone,
See below codes,
//: Playground - noun: a place where people can play
import Foundation
struct Foo {
var bar = 0
}
class A {
var foo = Foo() {
didSet {
print("foo changed")
}
}
}
let a = A()
for i in 1...5 {
a.foo.bar = i
