Re: [swift-users] Cannot pass immutable value as inout argument

Jordan Rose via swift-users schrieb am Mi. 17. Jan. 2018 um 01:38: > Oh no, you're right, I'm sorry. You can only do that with arrays at the > moment. We do have a bug for this already. > > Jordan > But couldn’t you call it like this: lgs_notify_params_t(notify:

Re: [swift-users] Cannot pass immutable value as inout argument

Oh no, you're right, I'm sorry. You can only do that with arrays at the moment. We do have a bug for this already. Jordan > On Jan 16, 2018, at 16:37, Roderick Mann wrote: > > Xcode can't properly parse the C header to show me the Swift signature, but > if I try

Re: [swift-users] Cannot pass immutable value as inout argument

Xcode can't properly parse the C header to show me the Swift signature, but if I try calling it like this: let p = lgs_notify_params_t(notify: lgs_notify_did_enter_background) lgs_notify(self.ctx, p) I get this error: Cannot convert value of type 'lgs_notify_params_t' to expected

Re: [swift-users] Cannot pass immutable value as inout argument

You can do this if you don't write '&', which incorporates the caveat that you're not passing a stable address. But please file a bug anyway, because the diagnostic should tell you that! Jordan > On Jan 16, 2018, at 13:10, Rick Mann via swift-users > wrote: > > Is it

[swift-users] Cannot pass immutable value as inout argument

Is it not possible for Swift to treat C API const pointers as something that can take let arguments? LGS_EXPORT bool lgs_notify(struct lgs_context_t* ctx, const lgs_notify_params_t* params); . . . let p = lgs_notify_params_t(...) lgs_notify(self.ctx, ) ^Cannot pass