Updates:
Status: Valid
Labels: Simplify
Comment #1 on issue 3544 by asmeu...@gmail.com: binomial should not get
expanded except when expand(func=True) is called on it
http://code.google.com/p/sympy/issues/detail?id=3544
Specifically, things like binomial(n, 5) should not auto
On Sun, Nov 18, 2012 at 10:03 PM, Chris Smith smi...@gmail.com wrote:
Hey very nice, but I actually want to later on substitute values for
lamb0..3, and if lamb is an undefined function as the above, how do I
do that?
f=Function('f')
f(1)+f(2)
f(1) + f(2)
_.replace(f, lambda x: x**2)
Hi
Hello and returning to this previous thread started by me:
On Tue, Nov 13, 2012 at 2:25 AM, Stefan Krastanov
krastanov.ste...@gmail.com wrote:
But we can
address this problem when we get an idea of the rest of what you are
trying to do.
Square_matrix_of_known_reals * Vector_of_unknown_pairs =
eqs=Tuple(*[A(0) + 5*A(1) - 2, -3*A(0) + 6*A(1) - 15])
solve(eqs, eqs.atoms(Function))
{A(0): -3, A(1): 1}
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On Sat, Dec 1, 2012 at 5:07 PM, Chris Smith smi...@gmail.com wrote:
eqs=Tuple(*[A(0) + 5*A(1) - 2, -3*A(0) + 6*A(1) - 15])
solve(eqs, eqs.atoms(Function))
{A(0): -3, A(1): 1}
Hi thanks for this! So does this mean that there is no need for
separate support for subscripted symbolic variables in
Hello,
from mathematical point of view, the floats are a kind of approximations.
So if someone
wants to have a rational form of one float, I think that it could be better
that this user must
convert first the float to one decimal and then to one rational. Not user
friendly but more
precise.
I
Hi thanks for this! So does this mean that there is no need for
separate support for subscripted symbolic variables in SymPy?
If the functions work, then no. But functions don't carry assumptions.
Having you raise questions like this helps to flesh out situations where
existing or new
On Sat, Dec 1, 2012 at 5:33 PM, Christophe BAL projet...@gmail.com wrote:
Hello,
from mathematical point of view, the floats are a kind of approximations.
So if someone
wants to have a rational form of one float, I think that it could be
better that this user must
convert first the float to
On Sat, Dec 1, 2012 at 5:32 PM, Chris Smith smi...@gmail.com wrote:
If the functions work, then no. But functions don't carry assumptions.
Can you clarify what you mean by assumptions?
And even though it seems (I haven't yet implemented that part of my
program yet) that it would be sufficient
On Sat, Dec 1, 2012 at 6:42 PM, Shriramana Sharma samj...@gmail.com wrote:
On Sat, Dec 1, 2012 at 5:32 PM, Chris Smith smi...@gmail.com wrote:
If the functions work, then no. But functions don't carry assumptions.
Can you clarify what you mean by assumptions?
And even though it seems (I
On Sat, Dec 1, 2012 at 6:46 PM, Chris Smith smi...@gmail.com wrote:
that's what symbols does for you; just store the result in an array if you
want:
a=symbols('a:11')
a[1]
a1
a
(a0, a1, a2, a3, a4, a5, a6, a7, a8, a9, a10)
But I already said that I can't use a Python list because I can't
Matrices can hold any type that inherits from Basic, the core SymPy type.
Matrix operations will often assume that these types have associated + and
* operators.
Many of the algorithms of matrices assume that the elements of a matrix are
SymPy expression objects (scalars).
From what you say the
I ran into this problem in MatrixExprs. We don't currently have a
subscripted symbol. It would be nice though.
In the following example
In [1]: X = MatrixSymbol('X', n, n)
In [2]: X[1, 2]
Out[2]: X₁₂
Ideally X[1, 2] is a Symbol that contains separate information for its
origin X and its
Hi,
I tried python lists and every thing seems fine to me-
ls=symbols('a:10')
ls
(a0, a1, a2, a3, a4, a5, a6, a7, a8, a9)
Now I call a function Sum (it sums up a series in particular, infinite
series)-
for i in range(10):
... Sum(1/(ls[i]**ls[i]),(ls[i],1,oo)).evalf()
...
1.29128599706266
On Sat, Dec 1, 2012 at 8:22 PM, Rishabh Dixit rishabhdixi...@gmail.com wrote:
for i in range(10):
... Sum(1/(ls[i]**ls[i]),(ls[i],1,oo)).evalf()
...
solve([ls[0]+5*ls[1]-2,-3*ls[0]+6*ls[1]-15])
{a0: -3, a1: 1}
Rishabh, basically the difference between what you are saying and I am
saying
Hi,
On the install page of the documentation
http://docs.sympy.org/0.7.2/install.html#git , it talks about
If you want to install SymPy, but still want to use the git version, you
can run from your repository:
$ setup.py develop
But, at least when I try it, setup.py it complains of an
try :
python setup.py develop
On 1 December 2012 09:07, Rathmann pkrathma...@gmail.com wrote:
Hi,
On the install page of the documentation
http://docs.sympy.org/0.7.2/install.html#git , it talks about
If you want to install SymPy, but still want to use the git version, you
can run from
Thanks. But that is what I tried?
python setup.py develop
usage: setup.py [global_opts] cmd1 [cmd1_opts] [cmd2 [cmd2_opts] ...]
or: setup.py --help [cmd1 cmd2 ...]
or: setup.py --help-commands
or: setup.py cmd --help
error: invalid command 'develop'
This is the setup.py in the
On Sat, Dec 1, 2012 at 12:26 PM, Rathmann pkrathma...@gmail.com wrote:
Thanks. But that is what I tried?
python setup.py develop
usage: setup.py [global_opts] cmd1 [cmd1_opts] [cmd2 [cmd2_opts] ...]
or: setup.py --help [cmd1 cmd2 ...]
or: setup.py --help-commands
or: setup.py cmd
You might need sudo python setupegg.py develop if you are not already root.
On Sat, Dec 1, 2012 at 11:59 PM, Sean Vig sean.v@gmail.com wrote:
On Sat, Dec 1, 2012 at 12:26 PM, Rathmann pkrathma...@gmail.com wrote:
Thanks. But that is what I tried?
python setup.py develop
usage:
Hi all,
Consider (with mp.dps = 30):
f = mp.mpf('0.1234123094834543252345098')
q = sy.Symbol('q')
x = f*q
Now, running lambdastr over the expression we find:
'lambda q: (0.1234123094834543252345098*q)'
which is curtailed by the fact that our mpf float will be interpreted as
a Python float.
On Dec 1, 2012, at 6:31 AM, Shriramana Sharma samj...@gmail.com wrote:
On Sat, Dec 1, 2012 at 6:46 PM, Chris Smith smi...@gmail.com wrote:
that's what symbols does for you; just store the result in an array if you
want:
a=symbols('a:11')
a[1]
a1
a
(a0, a1, a2, a3, a4, a5, a6, a7, a8, a9,
I think you should use a Symbol for f in your expression, and then add
{'f': mpf(...)} to the namespace dict used by lambdify.
Aaron Meurer
On Dec 1, 2012, at 4:14 PM, Freddie Witherden fred...@witherden.org wrote:
Hi all,
Consider (with mp.dps = 30):
f =
If you work with the current master you won't get the Indexed error:
from sympy import IndexedBase
A=IndexedBase('A')
solve([A[0] + 5*A[1] - 2, -3*A[0]+ 6*A[1] - 15])
[]
But no solution...so let's try the Tuple-atoms trick:
eqs=Tuple(*([A[0] + 5*A[1] - 2, -3*A[0]+ 6*A[1] - 15]))
On Sun, Dec 2, 2012 at 6:59 AM, Chris Smith smi...@gmail.com wrote:
If you work with the current master you won't get the Indexed error:
from sympy import IndexedBase
A=IndexedBase('A')
solve([A[0] + 5*A[1] - 2, -3*A[0]+ 6*A[1] - 15])
[]
But no solution...so let's try the Tuple-atoms
On Sat, Dec 1, 2012 at 7:13 PM, Matthew Rocklin mrock...@gmail.com wrote:
In the following example
In [1]: X = MatrixSymbol('X', n, n)
In [2]: X[1, 2]
Out[2]: X₁₂
Ideally X[1, 2] is a Symbol that contains separate information for its
origin X and its indices, 1, and 2. Alas, all it knows
On Sun, Dec 2, 2012 at 7:58 AM, Shriramana Sharma samj...@gmail.com wrote:
On Sun, Dec 2, 2012 at 6:59 AM, Chris Smith smi...@gmail.com wrote:
If you work with the current master you won't get the Indexed error:
from sympy import IndexedBase
A=IndexedBase('A')
solve([A[0] + 5*A[1] - 2,
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