Is there a reason it returns complex infinity versus just infinity?
Does it have to do with the assumptions about the variables?
Does anybody know an example where Mathematica returns just regular
infinity?
~Luke
On Jun 23, 10:23 am, Ondrej Certik ond...@certik.cz wrote:
2009/6/23 Roberto
Here is the link to the Wolfram Documentation for ComplexInfinity:
http://reference.wolfram.com/mathematica/ref/ComplexInfinity.html
Their one line documentation is:
represents a quantity with infinite magnitude, but undetermined
complex phase.
Everything I've tried in Wolfram returns
On 6/24/09, Luke hazelnu...@gmail.com wrote:
Here is the link to the Wolfram Documentation for ComplexInfinity:
http://reference.wolfram.com/mathematica/ref/ComplexInfinity.html
Their one line documentation is:
represents a quantity with infinite magnitude, but undetermined
complex
On Wed, Jun 24, 2009 at 9:44 AM, Fredrik
Johanssonfredrik.johans...@gmail.com wrote:
On 6/24/09, Luke hazelnu...@gmail.com wrote:
Here is the link to the Wolfram Documentation for ComplexInfinity:
http://reference.wolfram.com/mathematica/ref/ComplexInfinity.html
Their one line
Fredrik Johansson wrote:
On 6/24/09, Luke hazelnu...@gmail.com wrote:
Here is the link to the Wolfram Documentation for ComplexInfinity:
http://reference.wolfram.com/mathematica/ref/ComplexInfinity.html
Their one line documentation is:
represents a quantity with infinite magnitude,
Wolfram says that log(0) = -infinity.
Otherwise, limit(1/exp(log(-x), x,
0, +) = +infinity !
Check this link:
http://www53.wolframalpha.com/input/?i=+limit+(1%2Fexp(log(-x))+as+x-%3E0%2B
I don't think Mathematica computes limits by substituting x with 0 in
the expression, so it's not
In [2]: S(1)/0
Out[2]: ∞
Btw, so does wolframalpha:
http://www.wolframalpha.com/input/?i=1%2F0
In fact it returns ComplexInfinity for 1/0, and not Infinity as SymPy
currently does.
Roberto.
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On Mon, Jun 22, 2009 at 5:49 PM, Lukehazelnu...@gmail.com wrote:
Ondrej and I have had some discussion about what the trigonometric
functions tan, cot, sec, csc should return at singular points. It
seems there are a couple of options:
1) Return S.ComplexInfinity for things like tan(pi/2),
On Mon, Jun 22, 2009 at 18:49, Lukehazelnu...@gmail.com wrote:
Ondrej and I have had some discussion about what the trigonometric
functions tan, cot, sec, csc should return at singular points. It
seems there are a couple of options:
1) Return S.ComplexInfinity for things like tan(pi/2),
