I'm not saying that this sort of calculation shouldn't be doable, just
that the user needs to be explicit about asking for it to happen.
Also keep in mind that some evalf() calls can be very slow. This can
obviously happen if the expression is large, but it can also happen
for some Integrals and S
> This is a great example of code that ends up being dependent on
automatic evaluation behavior which makes that behavior harder to
remove.
If that is removed then the test will be changed to whatever mechanism will
allow the sign of `self - i` to be determined. And for an arbitrary
function I
This is somewhat off-topic, but perhaps related to what you are trying
to figure out, and anyway I see that this code is part of a PR
https://github.com/sympy/sympy/pull/25699. I don't like how this code
depends on the fact that self < i automatically evaluates to true or
false. This is a great exa
`eq=(cos(2)**2+sin(2)**2-1/S(10**120))` rounds to 1 but neither `eq<1` nor
`eq>1` evaluates but the correct value for `int(eq)` is 0.
/c
On Tuesday, September 19, 2023 at 8:14:35 AM UTC-5 Chris Smith wrote:
> Given
> ```
> def f(self):
> from sympy.core.numbers import int_valued
> r = s
