Re: [sympy] Sympy vs Numpy, better accuracy in precision?

On 11 April 2016 at 03:55, Amy Valhausen wrote: > In tried ; > > import mpmath > x = Float("1.4142", 950) > x**6000%400 > > But got the same sort of error message again ; > x = Float("1.4142", 950) > Traceback (most recent call last): > File "", line 1, in >

Re: [sympy] Sympy vs Numpy, better accuracy in precision?

Hi, regarding the below, is it possible to increase precision for this past (15) ? Im a little bit confused are you saying that a float set to the default precision will not return the accurate result but specifying the precision will? Also you mentioned a non float expression will return

Re: [sympy] Sympy vs Numpy, better accuracy in precision?

Hi Aaron, In tried ; import mpmath x = Float("1.4142", 950) x**6000%400 But got the same sort of error message again ; >>> x = Float("1.4142", 950) Traceback (most recent call last): File "", line 1, in NameError: name 'Float' is not defined Also, I thought I read recently that the float

Re: [sympy] Sympy vs Numpy, better accuracy in precision?

Oscar you mentioned below finding the # of digits using log and the code ; In [1]: from sympy import mpmath In [2]: mpmath.mp.dps = 950 In [3]: mpmath.mpf('1.4142') ** 6000 % 400 How accurate of a return do you feel this will give? Are we losing any data, will the return be very accurate?

Re: [sympy] Sympy vs Numpy, better accuracy in precision?

Hi Aaron I tried ; import mpmath x = mpmath.mpf("1.4142") x**6000 % 400 but this returned "32" for me, not 272 like you got? Also when I tried ; >>> x = Float("1.4142", 100) I got this error message ? Traceback (most recent call last): File "", line 1, in NameError: name 'Float' is not

Re: [sympy] Sympy vs Numpy, better accuracy in precision?

You can see how mpmath works here http://mpmath.org/doc/current/technical.html#representation-of-numbers. It basically uses man*2**exp binary representation. For instance In [249]: Float("0.1")._mpf_ Out[249]: (0, 3602879701896397, -55, 52) The first entry is the sign (positive). The next two

Re: [sympy] Sympy vs Numpy, better accuracy in precision?

On 5 April 2016 at 18:21, Isuru Fernando wrote: > > I think the current way of representing Floats is reasonable. > > Float internally keeps it in binary representation, so any non-terminating > number in base 2 is truncated when stored as a Float. That's why there is a > string

Re: [sympy] Sympy vs Numpy, better accuracy in precision?

On 5 April 2016 at 18:08, Aaron Meurer wrote: > On Tue, Apr 5, 2016 at 12:54 PM, Oscar Benjamin > wrote: >> >>> >>> I don't know if it should be considered a bug, but it's worth noting >>> that if you want SymPy to give the right precision in

Re: [sympy] Sympy vs Numpy, better accuracy in precision?

On Tue, Apr 5, 2016 at 12:54 PM, Oscar Benjamin wrote: > On 5 April 2016 at 17:15, Aaron Meurer wrote: >> On Tue, Apr 5, 2016 at 6:19 AM, Oscar Benjamin >> wrote: >>> >>> I though that it should be possible to easily do

Re: [sympy] Sympy vs Numpy, better accuracy in precision?

On 5 April 2016 at 17:15, Aaron Meurer wrote: > On Tue, Apr 5, 2016 at 6:19 AM, Oscar Benjamin > wrote: >> >> I though that it should be possible to easily do this with sympy >> Floats but it doesn't seem to work: >> >> In [1]: x = S(1.4142) >> >>

Re: [sympy] Sympy vs Numpy, better accuracy in precision?

On Tue, Apr 5, 2016 at 6:19 AM, Oscar Benjamin wrote: > On 5 April 2016 at 01:56, Amy Valhausen wrote: >> >> import numpy >> (np.longdouble(1.4142)** 6000 )%400 > ... >> >> # The library mpmath is a good solution > import sympy as smp

Re: [sympy] Sympy vs Numpy, better accuracy in precision?

On 5 April 2016 at 01:56, Amy Valhausen wrote: > > import numpy > (np.longdouble(1.4142)** 6000 )%400 ... > > # The library mpmath is a good solution import sympy as smp mp = smp.mpmath > mp.mp.dps = 50 # Computation precision is 50 digits 50 digits is

Re: [sympy] Sympy vs Numpy, better accuracy in precision?

6 at 8:56 PM, Amy Valhausen <amy.vaulhau...@gmail.com> wrote: > Sympy vs Numpy, better accuracy in precision? > > I've been trying to solve a problem with numpy and other code routines > to raise a base to a large power and then take the modulus. > > Precision accuracy is ve

[sympy] Sympy vs Numpy, better accuracy in precision?

Sympy vs Numpy, better accuracy in precision? I've been trying to solve a problem with numpy and other code routines to raise a base to a large power and then take the modulus. Precision accuracy is very important, speed isnt as much - although it would be convenient if I didnt have to wait