Actually, that's not quite true. SymPy has its own boolean types, and
x ^ x gives the SymPy BooleanFalse (S.false). The derivative of this
is 0 not because it interprets it as a numeric 0 but because it
doesn't depend on x, and diff automatically knows that the derivative
of any expression that
Am 31.05.2015 um 22:50 schrieb Aaron Meurer:
Perhaps we should make derivatives of booleans give TypeError. That
would make it much easier to see what is going on.
+1
Similarly, integer-valued functions should (probably?) emit a warning if
a derivative is taken. The derivative is technically
I also vote for the TypeError.
Le 31 mai 2015 23:17, Joachim Durchholz j...@durchholz.org a écrit :
Am 31.05.2015 um 22:50 schrieb Aaron Meurer:
Perhaps we should make derivatives of booleans give TypeError. That
would make it much easier to see what is going on.
+1
Similarly,
And because *x^x* means *x xor x* which numeric value is *0* or *1*
so the derivative is equal to zero.
*Christophe BAL*
*Enseignant de mathématiques en Lycée **et développeur Python amateur*
*---*
*French math teacher in a Lycée **and **Python **amateur developer*
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You received this
In [1]: x^x
Out[1]: False
In [2]: diff(False, x)
Out[2]: 0
You should use instead of *^* if you'd like to represent
exponentiation. The symbol ^ stands for XOR.
On Friday, 29 May 2015 23:17:11 UTC+2, Oscar wrote:
On 29 May 2015 22:06, Thomas Leitz unruh...@gmail.com javascript:
Hi,
the online shell at http://live.sympy.org/ tells me
diff(x^x,x) = 0
Why is that?
Tom
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On 29 May 2015 22:06, Thomas Leitz unruhsc...@gmail.com wrote:
Hi,
the online shell at http://live.sympy.org/ tells me
diff(x^x,x) = 0
Why is that?
^ doesn't do what you're expecting in Python. Use ** for exponentiation.
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Oscar
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