Standard expression language question

2002-01-28 Thread Pedro Diaz
Hi all. After executing the next two lines c:set var=foo1/c:set c:set var=foo value=$foo + 1/ the value of foo is 11 Is there a way to get that the value of foo be 2 using expression language? Thanks in advance. Pedro. -- To unsubscribe, e-mail: mailto:[EMAIL PROTECTED] For

RE: Standard expression language question

2002-01-28 Thread Mark Shead
] Subject: Standard expression language question Hi all. After executing the next two lines c:set var=foo1/c:set c:set var=foo value=$foo + 1/ the value of foo is 11 Is there a way to get that the value of foo be 2 using expression language? Thanks in advance. Pedro. -- To unsubscribe

Re: Standard expression language question

2002-01-28 Thread Pedro Diaz
the characters 1 and 1. Mark -Original Message- From: Pedro Diaz [mailto:[EMAIL PROTECTED]] Sent: Monday, January 28, 2002 10:19 AM To: [EMAIL PROTECTED] Subject: Standard expression language question Hi all. After executing the next two lines c:set var=foo1/c:set c:set var=foo

Re: Standard expression language question

2002-01-28 Thread Shawn Bayern
Hi Pedro, The answer will depend on the final expression language. For now, the behavior you note is caused by the experimental 'ECMAScript' expression language included with EA3; it performs concatenation on values it sees as Strings. In this experimental language, you can work around the