On Mon, 28 May 2007 08:55:39 -0400
Flavio daCosta <[EMAIL PROTECTED]> wrote:
> Remember from the php manual: References in php are not like C pointers.
> (they are symbol table aliases)
>
> On 05/28/2007 12:20 AM, Michael B Allen wrote:
>
> > for ($i = 0; $i < 3; $i++) {
unset($arr);
>
Remember from the php manual: References in php are not like C pointers.
(they are symbol table aliases)
On 05/28/2007 12:20 AM, Michael B Allen wrote:
> for ($i = 0; $i < 3; $i++) {
> $arr = array("a$i");
> $top[] = &$arr;
> $arr["key$i"] = "val$i";
> }
So what that is saying is t
Hey,
I'm having trouble with array references.
Consider the following code:
#!/usr/bin/php -q
I want to be able to update elements in $arr after it has been added to
$top. However, the assignment appears to make a copy (adding elements to
$arr are not in the $arr added to $top). So I thought p
