zl1...@gmx.com said:
> One other point. Attila mentioned using "LEA-M8T". I assume the T suffix
> relates to Time rather than the plain GPS. What is the difference? Apart
> from 50% higher cost.
If you use GPS for navigation, you need 4 satellites to get 4 equations that
you can solve for X,
It can easily be done using a variant of the dual conjugate regenerative
divider.Feed the 24 MHz signal into the LO port of a mixer.Use a dual bandpass
filters centred on 14MHz and 10MHz to filter the IF port amplify the outputs of
the bandpass filters and drive the mixer RF port with the
Hi
To filter out the close in noise on the output of the GPS module (regardless of
output frequency) you need a very narrow bandwidth loop. Cross over points in
the
0.01 Hz to < 0.001 Hz range are not at all unusual for these loops. Starting
off at a high(er)
frequency does not help in this
Hi all,
I'm fairly new here and might not fully understand things.
Earlier in this thread it was suggested that one lock an 8Mhz signal to a 10
Mhz signal by analogue methods.
To quote A Plummer:
"and it is relative easy to make 10MHz from 8MHz with analog frequency
manipulation, which
On 4/8/2016 7:19 PM, Nick Sayer via time-nuts wrote:
The instructable I wrote about it is at
http://www.instructables.com/id/Science-fair-How-accurate-is-the-AC-line-frequency/
There’s code for the Arduino and the Linux side as well as
schematics.
Hi Nick,
Awesome, thanks mucho!!!
thanks
Hi
Averaged over a long enough time (and without any hanging bridges) the
frequency accuracy
will be fine. The frequency accuracy of a 1 pps output on a GPS is “fine” on
the same basis. Since
200 KHz is a “round division” off of any of the likely TCXO’s you will not have
any jitter or spurs
I do not know what U blox does but I know when we use 200 KHz out of the 1
pps output on a $ 10 ublox 6 we consistently get better than 1 E-10 closer
to 1 E-11 out of the Morion have the data
Bert Kehren
In a message dated 4/9/2016 10:01:05 A.M. Eastern Daylight Time,
kb...@n1k.org
Hi
> On Apr 8, 2016, at 10:31 PM, Graham / KE9H wrote:
>
> The lowest jitter way to do this kind of conversion is to multiply the
> signal up to some common multiple frequency, then divide it back down to
> where you want to be. For instance, with 8 or 24 MHz, multiply
Hi
> On Apr 8, 2016, at 9:39 PM, time...@metachaos.net wrote:
>
> Hello Bob,
>
> Friday, April 8, 2016, 6:13:07 PM, you wrote:
>
>> Hi
>
>> If you start from a 24 MHz TCXO (different modules use different TCXO’s):
>
>> On an 8 MHz output, most of the time you divide by three.
>
>> On a 10
Hi
> On Apr 8, 2016, at 10:35 PM, Herbert Poetzl wrote:
>
> On Fri, Apr 08, 2016 at 06:13:07PM -0400, Bob Camp wrote:
>> Hi
>
>> If you start from a 24 MHz TCXO (different modules use
>> different TCXO’s):
>
>> On an 8 MHz output, most of the time you divide by three.
>
On Fri, 8 Apr 2016 21:31:31 -0500
"Graham / KE9H" wrote:
> The lowest jitter way to do this kind of conversion is to multiply the
> signal up to some common multiple frequency, then divide it back down to
> where you want to be. For instance, with 8 or 24 MHz, multiply up
Am I missing something? KISS. If you start out with a 10 MHz OCXO use a tvb
PIC to divide down to a lower frequency a 74HC74 to get symmetrical output
of a $ 10 u-blox 6 and the PIC and 86 XOR. If no PIC capability ebay has
LS90's for a one off.
Bert Kehren
In a message dated 4/9/2016
The lowest jitter way to do this kind of conversion is to multiply the
signal up to some common multiple frequency, then divide it back down to
where you want to be. For instance, with 8 or 24 MHz, multiply up to 240
MHz, then divide by 24 to get 10 MHz.
Modern clock generator chips have this
Hello Bob,
Friday, April 8, 2016, 6:13:07 PM, you wrote:
> Hi
> If you start from a 24 MHz TCXO (different modules use different TCXO’s):
> On an 8 MHz output, most of the time you divide by three.
> On a 10 MHz output, you need to divide by 2.4. The net result is that you
> divide by 2
On Fri, Apr 08, 2016 at 06:13:07PM -0400, Bob Camp wrote:
> Hi
> If you start from a 24 MHz TCXO (different modules use
> different TCXO’s):
> On an 8 MHz output, most of the time you divide by three.
> On a 10 MHz output, you need to divide by 2.4.
> The net result is that you divide by 2
"Could you elaborate on this a little if time permits? I'm more a
'digital person' but it sounds interesting. Thanks in advance, Herbert "
Yes Herbert
here is;
first divide 24MHz by two you get a very good quality absolute 50% duty
cycle 12MHz, than you feed that 12MHx into mixer [which could
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