Without examining details in your message I can ask:
Structure should be (maybe it is already?)
Webapp
WEB-INF
web.xml
classess
lib
Etc.
Then, shouldn't be you calling
http://localhost:8080/webapp/XML_RPC_Testserveur
Instead?
Regards.
José Ernesto Echeverría
[EMAIL PROTECTED]
-----Original Message-----
From: Christian Ruediger [mailto:[EMAIL PROTECTED]
Sent: Viernes, 01 de Octubre de 2004 08:56 a.m.
To: Tomcat Users List
Subject: [tomcat] deploy simple HTTP doPost servlet to tomcat 5.0.28
Hi folks,
after trying the complex aproach without any success, I started a lowtech
approach. I simply want a small servlet deployed. Can't be too complicated.
What I have:
Apache Tomcat 5.0.28 Server
Win 2000
j2sdk1.4.2_05
I constructed the following structure in tomcats webapp folder:
webapp -
- classes
- testserveur
- XML_RPC_Servlet.class
- libs
- web.xml
(dont bother the name XML_RPC_Servlet.its for future purposes.
currently only text is displayed -> see code below)
web.xml is as follows:
<!DOCTYPE web-app PUBLIC "-//Sun Microsystems, Inc.// DTD WebApplication
2.2//EN"
"http://java.sun.com/j2ee/dtds/web-app_2.2.dtd";>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee";
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd";
version="2.4">
<display-name>Testservlet</display-name>
<context-parameter>
<param-name>Lieblingsfarbe</param-name>
<param-value>rot</param-value>
</context-parameter>
<servlet>
<servlet-name>XML_RPC_Testserveur</servlet-name>
<servlet-class>
testserveur.RPC_XML_Servlet
</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>XML_RPC_Testserveur</servlet-name>
<url-pattern>/XML_RPC_Testserveur</url-pattern>
</servlet-mapping>
</web-app>
code is as follows:
public class XML_RPC_Servlet extends HttpServlet{
protected void doGet(HttpServletRequest req,
HttpServletResponse res)
throws ServletException, IOException
{
res.setContentType("text/html");
PrintWriter out = res.getWriter();
out.println("<HTML><HEAD><TITLE>Hello There!</TITLE>"+
"</HEAD><BODY>Hello There!</BODY></HTML>");
out.close();
}
public String getServletInfo()
{
return "HelloClientServlet 1.0 by Stefan Zeiger";
}
}
What i did:
-Started Tomcat (is configured to localhost:8080) -opened Browser -typed
http://localhost:8080/XML_RPC_Testserveur
- got only a message that the resource is unavailable (in french):
*****************************
type Rapport d'état
message /XML_RPC_Testserveur
description La ressource demandée (/XML_RPC_Testserveur) n'est pas
disponible.
******************************
I am searching for a reason of this for nearly a day.
Is there anyone who can help me?
Thanx Christian
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