RE: Multiple tomcat services?
Jens, Uncheck the 'Service' option while installing. Windows does not allow to have two services with same name. So, don't install as Service. Rgds, Hardik Tank --- Jens Nordberg [EMAIL PROTECTED] wrote: How do you mean? The install program for Tomcat 5.5.9 doesn't allow me to change the name, or does it? As far as I can tell, I can only specify install directory, HTTP port, user name, password and jre. /Jens -Original Message- From: Arup Vidyerthy [mailto:[EMAIL PROTECTED] Sent: den 28 september 2005 16:20 To: 'Tomcat Users List' Subject: RE: Multiple tomcat services? Install it under a different name -Original Message- From: Jens Nordberg [mailto:[EMAIL PROTECTED] Sent: 28 September 2005 15:13 To: tomcat-user@jakarta.apache.org Subject: Multiple tomcat services? Hi, I'm trying to install multiple tomcats on my machine, which works quite well except for one thing. When I'm installing the second instance of Tomcat, I get the following error: Failed to install Tomcat5 service. Check your settings and permissions. Ignore and continue anyway (not recommended)? I chose to ignore and continue. Tomcat then installs, but no service is added in windows services. If I go to the bin library of the second tomcat and press tomcat5w, it opens the _first_ instance's application. Is there a way to get two services going when I have multiple tomcats? The first instance is a tomcat 5.0 and the second is a tomcat 5.5.9. Any suggestions? Kind regards /Jens ___ To help you stay safe and secure online, we've developed the all new Yahoo! Security Centre. http://uk.security.yahoo.com - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] __ Yahoo! Mail - PC Magazine Editors' Choice 2005 http://mail.yahoo.com - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: SOAP on TOMCAT 5.0
hi, u will get unsupported major.minor version 48.0 error when ur code has been compiled using higher version of JDK (may be 1.5) and u r running it using lower version of JDK/JRE (may be 1.4) check ur setup and JRE/JDK once again. rgds, Hardik Tank --- [EMAIL PROTECTED] wrote: Hi Guys, Some help required on using SOAP on Tomcat 5.0. I need to configure SOAP 2.3.1 with Tomcat 5.0 locally on my machine. Following are the things I did: 1) Copied the soap.war file under the webapps directory. 2)Set the class paths in my system 3) copied the latest version of activation.jar,mail.jar and xercesImpl.jar onto the lib directory of tomcat I am able to get the soap home page: http://localhost:8080/soap I am also able to Run the admin tool and deploy a sample webservice using the admin tool. Also the the webservice is listed as a deployed component. NOTE: Right now I am running the service and client from same server. However the problem persisted when I used different servers(Tomcat again) on different machines as well. As I see this leads to the creation of DeployedServices.ds xml descriptor on soap folder in tomcat. Yet I am not able to deploy the service through command line neither am I able to run the client program through command line. Both these actions throw the same error messages: java.lang.UnsupportedClassVersion error: org/w3c/dom/Node (unsupported major.minor version 48.0) As I understand this is because default dom api's in Tomcat are older versions which support Level 1 parsing. However all latest apis which might be used by SOAP are Level3 based. Hence I included the xml-apis.jar and xercesImpl.jar in the /common/endorsed directory in Tomcat. This is supposed to override the use of default jars. Still I am getting the same error. Is there something else I am missing too. Any sort of help on this welcome. Just wanted to give it another shot else I need to reinstall the latest version on Tomcat that is supposed to be free from this error Thanks Niladri Confidentiality Notice The information contained in this electronic message and any attachments to this message are intended for the exclusive use of the addressee(s) and may contain confidential or privileged information. If you are not the intended recipient, please notify the sender at Wipro or [EMAIL PROTECTED] immediately and destroy all copies of this message and any attachments. __ Yahoo! Mail - PC Magazine Editors' Choice 2005 http://mail.yahoo.com - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: servlet mapping and url
you can configure your web.xml file and make index.jsp file as an welcome file using, welcome-file-list welcome-fileindex.jsp/welcome-file /welcome-file-list now, create index.jsp file which will simply forward the request to your servlet! Rgds, Hardik --- s s [EMAIL PROTECTED] wrote: i want to invoke a servlet using url like http://localhost:8080 only i have done it using http://localhost:8080/index.html where index.html is a servlet. Is it possible to load this servlet as a default just like a default web page. The point is i want a servlet to recieve a request when url http://localhost:8080 is referenced i.e without the servlet name. is it possible? - Yahoo! Mail Mobile Take Yahoo! Mail with you! Check email on your mobile phone. Yahoo! Sports Rekindle the Rivalries. Sign up for Fantasy Football http://football.fantasysports.yahoo.com - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Unauthorized users get 403
you can configure web.xml file with following entry, error-page error-code403/error-code location/errorPage403.jsp/location /error-page you can show proper error message in errorPage403.jsp page or if u want to show login page then put 'login.jsp?error=403' as location and handle the passed parameter in login.jsp page Rgds, Hardik --- David Newman [EMAIL PROTECTED] wrote: I have setup an application in tomcat 5.5.9 with FORM based authentication. Everything works, however, I've noticed that if a user successfully authenticates, but is not authorized by being in the specified role, they get the 403 not authorized page. I would prefer they just get the login page again. Is this possible? -Dave - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] __ Do You Yahoo!? Tired of spam? Yahoo! Mail has the best spam protection around http://mail.yahoo.com - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Changing the URL
Hi Mohit, For the root application means to access your application like http://localhost:8080/ do following, Option 1: - Rename webapps/ROOT folder to any other name - Rename your application folder in the webapps to ROOT Note: But this is not a proper approach!! Option 2: - In the conf/server.xml file add following entry for your application, Context path= docBase=PED debug=0/ - For information on Context refer Tomcat Configuration manual. Regarding alias for the host, you can set this only you have two names configured by your N/W admin in the DNS entries. Bcs, from the browser it will try to map IP for the given host name, which will use DNS entries. To avoid typing port, you can set default port to 80 for your tomcat HTTP connector in conf/server.xml file. For SSL, refer tomcat documentation for setup details. Hope, this will help you somewhat! Bye Hardik --- Passsionate [EMAIL PROTECTED] wrote: Hi, I am using Tomcat -5.0.25 , i had made an application named PED and placed it in the webapps so when i type http://localhost:8080/PED . The application is working fine. Now what i want is to do something so that when i type www.PED.com , the application should run. For this i read the Tomcat Docs came to know about Alias Tag in HOST. And also of appBase attribute form where our applications are found. I put the Alias Tag and gave the hello. And also changed the appBase attrib. to webapps/PED . Now i thought that writing http://hello:8080 would start my application but that didn't happened.Even only placing the Alias tag and trying http://hello:8080/PED didn't work . Please let me know about this and also how the port is mapped . Also how can i introduce SSL in my appl. Tell me the steps or the relevant link. I am in immediate need. Please help me out. Thanks in advance. Bye Mohit. Yahoo! India Matrimony: Find your life partneronline. __ Do you Yahoo!? Take Yahoo! Mail with you! Get it on your mobile phone. http://mobile.yahoo.com/maildemo - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: can anybody please help me!!
Hi, Are you using init() method of the servlet for fetching init parameters like this? String str = getServletConfig().getInitParameter(param1); Rgrds, Hardik --- Raasi Potluri [EMAIL PROTECTED] wrote: Dear Friends, I have written a simple servlet which reads a init parameter from the web.xml file and displays on the browser. I'm a beginner and trying to learn simple servlets, I have reached where I can read some init params from the web.xml file and displays on the browser, but all the simple servlets are working without any hassle, but reading init parameter returns null in the servlet, because I triend to print that on to the console, but it returns null, please help me, awaiting a reply, regards Raasi web.xml looks like this ?xml version=1.0 encoding=ISO-8859-1? !-- Copyright 2004 The Apache Software Foundation Licensed under the Apache License, Version 2.0 (the License); you may not use this file except in compliance with the License. You may obtain a copy of the License at http://www.apache.org/licenses/LICENSE-2.0 Unless required by applicable law or agreed to in writing, software distributed under the License is distributed on an AS IS BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the License for the specific language governing permissions and limitations under the License. -- web-app xmlns=http://java.sun.com/xml/ns/j2ee; xmlns:xsi=http://www.w3.org/2001/XMLSchema-instance; xsi:schemaLocation=http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd; version=2.4 display-nameWelcome to Tomcat/display-name description Welcome to Tomcat /description !-- JSPC servlet mappings start -- servlet servlet-nameorg.apache.jsp.index_jsp/servlet-name servlet-classorg.apache.jsp.index_jsp/servlet-class /servlet servlet-mapping servlet-nameorg.apache.jsp.index_jsp/servlet-name url-pattern/index.jsp/url-pattern /servlet-mapping servlet servlet-nameHelloServlet/servlet-name servlet-classHelloServlet/servlet-class /servlet servlet-mapping servlet-nameHelloServlet/servlet-name url-pattern/HelloServlet/url-pattern /servlet-mapping servlet servlet-nameInternationalizedHelloWorld/servlet-name servlet-classcom.jspbook.InternationalizedHelloWorld/servlet-class init-param param-namegreeting/param-name param-valueKisahairetu/param-value /init-param /servlet servlet-mapping servlet-nameInternationalizedHelloWorld/servlet-name url-pattern/InternationalizedHelloWorld/url-pattern /servlet-mapping !-- JSPC servlet mappings end -- /web-app __ Do you Yahoo!? Yahoo! Mail - Helps protect you from nasty viruses. http://promotions.yahoo.com/new_mail - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] __ Do you Yahoo!? Yahoo! Mail - 250MB free storage. Do more. Manage less. http://info.mail.yahoo.com/mail_250 - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: can anybody please help me!!
Hi,
Use init(ServletConfig config) method of servlet for
init parameters. bcs, init parameters will be set only
once it is initialised... so, u have to do the same in
the init() method only...
thanks.
--- Raasi Potluri [EMAIL PROTECTED] wrote:
Hello Hardik,
thanks for your reply, yeas, I'm using the same code
as you written,
thanx eversomuch, please help me out
the code looks like this
[code]
package com.jspbook;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class InternationalizedHelloWorld extends
HttpServlet {
public void doGet(HttpServletRequest request,
HttpServletResponse response) throws IOException,
ServletException {
response.setContentType(text/html);
PrintWriter out = response.getWriter();
String greeting;
greeting =
getServletConfig().getInitParameter(greeting);
if(greeting != null) {
System.out.println(lopaliki vachav);
out.println(html);
out.println(head);
out.println(titleShabbu Bhai/title);
out.println(/head);
out.println(body);
out.println(h1 + greeting + /h1);
out.println(/body);
out.println(/html);
}
else {
System.out.println(bayate unnav);
out.println(html);
out.println(head);
out.println(titleShabbu Bhai/title);
out.println(/head);
out.println(body);
out.println(h1Emiledura Dunna/h1);
out.println(/body);
out.println(/html);
}
}
}
[code]
--- Hardik Tank [EMAIL PROTECTED] wrote:
Hi,
Are you using init() method of the servlet for
fetching init parameters like this?
String str =
getServletConfig().getInitParameter(param1);
Rgrds,
Hardik
--- Raasi Potluri [EMAIL PROTECTED] wrote:
Dear Friends,
I have written a simple servlet which reads a
init
parameter from the web.xml file and displays on
the
browser. I'm a beginner and trying to learn
simple
servlets, I have reached where I can read some
init
params from the web.xml file and displays on the
browser, but all the simple servlets are working
without any hassle, but reading init parameter
returns
null in the servlet, because I triend to print
that
on
to the console, but it returns null, please help
me,
awaiting a reply, regards Raasi
web.xml looks like this
?xml version=1.0 encoding=ISO-8859-1?
!--
Copyright 2004 The Apache Software Foundation
Licensed under the Apache License, Version 2.0
(the
License);
you may not use this file except in compliance
with
the License.
You may obtain a copy of the License at
http://www.apache.org/licenses/LICENSE-2.0
Unless required by applicable law or agreed to
in
writing, software
distributed under the License is distributed
on
an
AS IS BASIS,
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND,
either
express or implied.
See the License for the specific language
governing
permissions and
limitations under the License.
--
web-app xmlns=http://java.sun.com/xml/ns/j2ee;
xmlns:xsi=http://www.w3.org/2001/XMLSchema-instance;
xsi:schemaLocation=http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd;
version=2.4
display-nameWelcome to Tomcat/display-name
description
Welcome to Tomcat
/description
!-- JSPC servlet mappings start --
servlet
servlet-nameorg.apache.jsp.index_jsp/servlet-name
servlet-classorg.apache.jsp.index_jsp/servlet-class
/servlet
servlet-mapping
servlet-nameorg.apache.jsp.index_jsp/servlet-name
url-pattern/index.jsp/url-pattern
/servlet-mapping
servlet
servlet-nameHelloServlet/servlet-name
servlet-classHelloServlet/servlet-class
/servlet
servlet-mapping
servlet-nameHelloServlet/servlet-name
url-pattern/HelloServlet/url-pattern
/servlet-mapping
servlet
servlet-nameInternationalizedHelloWorld/servlet-name
servlet-classcom.jspbook.InternationalizedHelloWorld/servlet-class
init-param
param-namegreeting/param-name
param-valueKisahairetu/param-value
/init-param
/servlet
servlet-mapping
servlet-nameInternationalizedHelloWorld/servlet-name
url-pattern/InternationalizedHelloWorld/url-pattern
/servlet-mapping
!-- JSPC servlet mappings end --
/web-app
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