Sorry Chinni,

but that didnt't work. Why isn't there a connection between the server and
the compiler?

Dominik

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Gesendet: Donnerstag, 7. Februar 2002 20:15
An: Tomcat Users List
Betreff: Re: Newbie problem with reading init params




You actually read them from ServletContext not from the ServletConfig.

You can get the Servlet Context by doing...

ServletContext sc = getServletContext();


Hope this helps.

-Chinni.





                    Dominik
                    Jednoralski          To:
[EMAIL PROTECTED]
                    <tomcat@lime-        cc:
                    design.de>           Subject:     Newbie problem with
reading init
                                         params
                    02/07/02
                    12:02 PM
                    Please
                    respond to
                    Tomcat Users
                    List






Hey Guys,

I have a problem with getting my init-params from the web.xml-file.
These are the parameters I inserted into the
webapps/root/web-inf/web.xml-file:

<web-app>
  <servlet>
    <servlet-name>ShowMsg</servlet-name>
    <servlet-class>limeservlets.ShowMessage</servlet-class>
    <init-param>
      <param-name>message</param-name>
      <param-value>Nerv-Serv</param-value>
    </init-param>
    <init-param>
      <param-name>repeats</param-name>
      <param-value>5</param-value>
    </init-param>
  </servlet>
</web-app>

Now I failed to read these parameters with the follwing servlet:


package limeservlets;

import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;

 public class ShowMessage extends HttpServlet {
    private String message;
    private String defaultMessage = "Leider keine Nachricht.";
    private int repeats = 1;

    public void init (ServletConfig config) throws ServletException{
       super.init(config);
       message = config.getInitParameter("message");
       if (message == null) {
                message = defaultMessage;
       }

       try {
                 String repeatString = config.getInitParameter
("repeats");
                 repeats = Integer.parseInt(repeatString);
       } catch (NumberFormatException nfe){}
    }

    public void doGet (HttpServletRequest request, HttpServletResponse
response)
       throws ServletException, IOException{
           response.setContentType("text/html");
           PrintWriter out = response.getWriter();
           String title = "The Servlet which shows a message!";

           out.println(ServletUtilities.headWithTitle(title) +
           "<body bgcolor=#fdf5f6>\n<h1>"+ title + "</h1><br>");
           for (int i = 0; i < repeats; i ++) {
           out.println(message + "<br>");
           }
           out.println("</body></html>");
    }
 }


Does anyone know the reason for that? I for myself don't have a clue-
I'm
not really
into configuring servers...

Dominik Jednoralski

. Lime Design Mediengestaltung
. Lilienstr. 23
. 63768 Hvsbach
. Tel. 06021.550470

. visit www.lime-design.de

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