can anybody please help me!!

2004-12-27 Thread Raasi Potluri
Dear Friends,

I have written a simple servlet which reads a init
parameter from the web.xml file and displays on the
browser. I'm a beginner and trying to learn simple
servlets, I have reached where I can read some init
params from the web.xml file and displays on the
browser, but all the simple servlets are working
without any hassle, but reading init parameter returns
null in the servlet, because I triend to print that on
to the console, but it returns null, please help me,
awaiting a reply, regards Raasi

web.xml looks like this

?xml version=1.0 encoding=ISO-8859-1?
!--
  Copyright 2004 The Apache Software Foundation

  Licensed under the Apache License, Version 2.0 (the
License);
  you may not use this file except in compliance with
the License.
  You may obtain a copy of the License at

  http://www.apache.org/licenses/LICENSE-2.0

  Unless required by applicable law or agreed to in
writing, software
  distributed under the License is distributed on an
AS IS BASIS,
  WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either
express or implied.
  See the License for the specific language governing
permissions and
  limitations under the License.
--

web-app xmlns=http://java.sun.com/xml/ns/j2ee;
   
xmlns:xsi=http://www.w3.org/2001/XMLSchema-instance;
   
xsi:schemaLocation=http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd;
version=2.4

  display-nameWelcome to Tomcat/display-name
  description
 Welcome to Tomcat
  /description


!-- JSPC servlet mappings start --

servlet
   
servlet-nameorg.apache.jsp.index_jsp/servlet-name
   
servlet-classorg.apache.jsp.index_jsp/servlet-class
/servlet

servlet-mapping
   
servlet-nameorg.apache.jsp.index_jsp/servlet-name
url-pattern/index.jsp/url-pattern
/servlet-mapping


servlet
servlet-nameHelloServlet/servlet-name
servlet-classHelloServlet/servlet-class
/servlet


servlet-mapping
servlet-nameHelloServlet/servlet-name
url-pattern/HelloServlet/url-pattern
/servlet-mapping

servlet

servlet-nameInternationalizedHelloWorld/servlet-name

servlet-classcom.jspbook.InternationalizedHelloWorld/servlet-class
init-param
   param-namegreeting/param-name
   param-valueKisahairetu/param-value
/init-param
/servlet

servlet-mapping

servlet-nameInternationalizedHelloWorld/servlet-name

url-pattern/InternationalizedHelloWorld/url-pattern
/servlet-mapping

!-- JSPC servlet mappings end --

/web-app




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Re: can anybody please help me!!

2004-12-27 Thread Hardik Tank
Hi,

Are you using init() method of the servlet for
fetching init parameters like this?

String str =
getServletConfig().getInitParameter(param1);


Rgrds,
Hardik


--- Raasi Potluri [EMAIL PROTECTED] wrote:

 Dear Friends,
 
 I have written a simple servlet which reads a init
 parameter from the web.xml file and displays on the
 browser. I'm a beginner and trying to learn simple
 servlets, I have reached where I can read some init
 params from the web.xml file and displays on the
 browser, but all the simple servlets are working
 without any hassle, but reading init parameter
 returns
 null in the servlet, because I triend to print that
 on
 to the console, but it returns null, please help me,
 awaiting a reply, regards Raasi
 
 web.xml looks like this
 
 ?xml version=1.0 encoding=ISO-8859-1?
 !--
   Copyright 2004 The Apache Software Foundation
 
   Licensed under the Apache License, Version 2.0
 (the
 License);
   you may not use this file except in compliance
 with
 the License.
   You may obtain a copy of the License at
 
   http://www.apache.org/licenses/LICENSE-2.0
 
   Unless required by applicable law or agreed to in
 writing, software
   distributed under the License is distributed on an
 AS IS BASIS,
   WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND,
 either
 express or implied.
   See the License for the specific language
 governing
 permissions and
   limitations under the License.
 --
 
 web-app xmlns=http://java.sun.com/xml/ns/j2ee;


xmlns:xsi=http://www.w3.org/2001/XMLSchema-instance;

 xsi:schemaLocation=http://java.sun.com/xml/ns/j2ee
 http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd;
 version=2.4
 
   display-nameWelcome to Tomcat/display-name
   description
  Welcome to Tomcat
   /description
 
 
 !-- JSPC servlet mappings start --
 
 servlet


servlet-nameorg.apache.jsp.index_jsp/servlet-name


servlet-classorg.apache.jsp.index_jsp/servlet-class
 /servlet
 
 servlet-mapping


servlet-nameorg.apache.jsp.index_jsp/servlet-name
 url-pattern/index.jsp/url-pattern
 /servlet-mapping
 
 
 servlet
 servlet-nameHelloServlet/servlet-name
 servlet-classHelloServlet/servlet-class
 /servlet
 
 
 servlet-mapping
 servlet-nameHelloServlet/servlet-name
 url-pattern/HelloServlet/url-pattern
 /servlet-mapping
 
 servlet
 

servlet-nameInternationalizedHelloWorld/servlet-name
 

servlet-classcom.jspbook.InternationalizedHelloWorld/servlet-class
   init-param
  param-namegreeting/param-name
  param-valueKisahairetu/param-value
   /init-param
 /servlet
 
 servlet-mapping
 

servlet-nameInternationalizedHelloWorld/servlet-name
 

url-pattern/InternationalizedHelloWorld/url-pattern
 /servlet-mapping
 
 !-- JSPC servlet mappings end --
 
 /web-app
 
 
 
   
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Re: can anybody please help me!!

2004-12-27 Thread Raasi Potluri
Hello Hardik,

thanks for your reply, yeas, I'm using the same code
as you written,

thanx eversomuch, please help me out

the code looks like this

[code]


package com.jspbook;

import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;

public class InternationalizedHelloWorld extends
HttpServlet {

public void doGet(HttpServletRequest request,
HttpServletResponse response) throws IOException,
ServletException {

response.setContentType(text/html);

PrintWriter out = response.getWriter();

String greeting;

greeting =
getServletConfig().getInitParameter(greeting);

if(greeting != null) {

System.out.println(lopaliki vachav);

out.println(html);
out.println(head);
out.println(titleShabbu Bhai/title);
out.println(/head);
out.println(body);
out.println(h1 + greeting + /h1);
out.println(/body);
out.println(/html);

}

else {

System.out.println(bayate unnav);

out.println(html);
out.println(head);
out.println(titleShabbu Bhai/title);
out.println(/head);
out.println(body);
out.println(h1Emiledura Dunna/h1);
out.println(/body);
out.println(/html);


}   

 }
  }


[code]


--- Hardik Tank [EMAIL PROTECTED] wrote:

 Hi,
 
 Are you using init() method of the servlet for
 fetching init parameters like this?
 
 String str =
 getServletConfig().getInitParameter(param1);
 
 
 Rgrds,
 Hardik
 
 
 --- Raasi Potluri [EMAIL PROTECTED] wrote:
 
  Dear Friends,
  
  I have written a simple servlet which reads a init
  parameter from the web.xml file and displays on
 the
  browser. I'm a beginner and trying to learn simple
  servlets, I have reached where I can read some
 init
  params from the web.xml file and displays on the
  browser, but all the simple servlets are working
  without any hassle, but reading init parameter
  returns
  null in the servlet, because I triend to print
 that
  on
  to the console, but it returns null, please help
 me,
  awaiting a reply, regards Raasi
  
  web.xml looks like this
  
  ?xml version=1.0 encoding=ISO-8859-1?
  !--
Copyright 2004 The Apache Software Foundation
  
Licensed under the Apache License, Version 2.0
  (the
  License);
you may not use this file except in compliance
  with
  the License.
You may obtain a copy of the License at
  
http://www.apache.org/licenses/LICENSE-2.0
  
Unless required by applicable law or agreed to
 in
  writing, software
distributed under the License is distributed on
 an
  AS IS BASIS,
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND,
  either
  express or implied.
See the License for the specific language
  governing
  permissions and
limitations under the License.
  --
  
  web-app xmlns=http://java.sun.com/xml/ns/j2ee;
 
 

xmlns:xsi=http://www.w3.org/2001/XMLSchema-instance;
 
 
 xsi:schemaLocation=http://java.sun.com/xml/ns/j2ee
  http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd;
  version=2.4
  
display-nameWelcome to Tomcat/display-name
description
   Welcome to Tomcat
/description
  
  
  !-- JSPC servlet mappings start --
  
  servlet
 
 

servlet-nameorg.apache.jsp.index_jsp/servlet-name
 
 

servlet-classorg.apache.jsp.index_jsp/servlet-class
  /servlet
  
  servlet-mapping
 
 

servlet-nameorg.apache.jsp.index_jsp/servlet-name
  url-pattern/index.jsp/url-pattern
  /servlet-mapping
  
  
  servlet
  servlet-nameHelloServlet/servlet-name
 
 servlet-classHelloServlet/servlet-class
  /servlet
  
  
  servlet-mapping
  servlet-nameHelloServlet/servlet-name
  url-pattern/HelloServlet/url-pattern
  /servlet-mapping
  
  servlet
  
 

servlet-nameInternationalizedHelloWorld/servlet-name
  
 

servlet-classcom.jspbook.InternationalizedHelloWorld/servlet-class
  init-param
 param-namegreeting/param-name
 param-valueKisahairetu/param-value
  /init-param
  /servlet
  
  servlet-mapping
  
 

servlet-nameInternationalizedHelloWorld/servlet-name
  
 

url-pattern/InternationalizedHelloWorld/url-pattern
  /servlet-mapping
  
  !-- JSPC servlet mappings end --
  
  /web-app
  
  
  
  
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Re: can anybody please help me!!

2004-12-27 Thread Hardik Tank
Hi,

Use init(ServletConfig config) method of servlet for
init parameters. bcs, init parameters will be set only
once it is initialised... so, u have to do the same in
the init() method only...

thanks.

--- Raasi Potluri [EMAIL PROTECTED] wrote:

 Hello Hardik,
 
 thanks for your reply, yeas, I'm using the same code
 as you written,
 
 thanx eversomuch, please help me out
 
 the code looks like this
 
 [code]
 
 
 package com.jspbook;
 
 import java.io.*;
 import javax.servlet.*;
 import javax.servlet.http.*;
 
 public class InternationalizedHelloWorld extends
 HttpServlet {
 
 public void doGet(HttpServletRequest request,
 HttpServletResponse response) throws IOException,
 ServletException {
 
   response.setContentType(text/html);
 
   PrintWriter out = response.getWriter();
 
   String greeting;
 
   greeting =
 getServletConfig().getInitParameter(greeting);
   
   if(greeting != null) {
 
   System.out.println(lopaliki vachav);
   
   out.println(html);
   out.println(head);
   out.println(titleShabbu Bhai/title);
   out.println(/head);
   out.println(body);
   out.println(h1 + greeting + /h1);
   out.println(/body);
   out.println(/html);
 
   }
 
   else {
 
   System.out.println(bayate unnav);
 
   out.println(html);
   out.println(head);
   out.println(titleShabbu Bhai/title);
   out.println(/head);
   out.println(body);
   out.println(h1Emiledura Dunna/h1);
   out.println(/body);
   out.println(/html);
   
   
   }   
   
  }
   }
 
 
 [code]
 
 
 --- Hardik Tank [EMAIL PROTECTED] wrote:
 
  Hi,
  
  Are you using init() method of the servlet for
  fetching init parameters like this?
  
  String str =
  getServletConfig().getInitParameter(param1);
  
  
  Rgrds,
  Hardik
  
  
  --- Raasi Potluri [EMAIL PROTECTED] wrote:
  
   Dear Friends,
   
   I have written a simple servlet which reads a
 init
   parameter from the web.xml file and displays on
  the
   browser. I'm a beginner and trying to learn
 simple
   servlets, I have reached where I can read some
  init
   params from the web.xml file and displays on the
   browser, but all the simple servlets are working
   without any hassle, but reading init parameter
   returns
   null in the servlet, because I triend to print
  that
   on
   to the console, but it returns null, please help
  me,
   awaiting a reply, regards Raasi
   
   web.xml looks like this
   
   ?xml version=1.0 encoding=ISO-8859-1?
   !--
 Copyright 2004 The Apache Software Foundation
   
 Licensed under the Apache License, Version 2.0
   (the
   License);
 you may not use this file except in compliance
   with
   the License.
 You may obtain a copy of the License at
   
 http://www.apache.org/licenses/LICENSE-2.0
   
 Unless required by applicable law or agreed to
  in
   writing, software
 distributed under the License is distributed
 on
  an
   AS IS BASIS,
 WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND,
   either
   express or implied.
 See the License for the specific language
   governing
   permissions and
 limitations under the License.
   --
   
   web-app xmlns=http://java.sun.com/xml/ns/j2ee;
  
  
 

xmlns:xsi=http://www.w3.org/2001/XMLSchema-instance;
  
  
 
 xsi:schemaLocation=http://java.sun.com/xml/ns/j2ee
   http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd;
   version=2.4
   
 display-nameWelcome to Tomcat/display-name
 description
Welcome to Tomcat
 /description
   
   
   !-- JSPC servlet mappings start --
   
   servlet
  
  
 

servlet-nameorg.apache.jsp.index_jsp/servlet-name
  
  
 

servlet-classorg.apache.jsp.index_jsp/servlet-class
   /servlet
   
   servlet-mapping
  
  
 

servlet-nameorg.apache.jsp.index_jsp/servlet-name
   url-pattern/index.jsp/url-pattern
   /servlet-mapping
   
   
   servlet
  
 servlet-nameHelloServlet/servlet-name
  
  servlet-classHelloServlet/servlet-class
   /servlet
   
   
   servlet-mapping
  
 servlet-nameHelloServlet/servlet-name
   url-pattern/HelloServlet/url-pattern
   /servlet-mapping
   
   servlet
   
  
 

servlet-nameInternationalizedHelloWorld/servlet-name
   
  
 

servlet-classcom.jspbook.InternationalizedHelloWorld/servlet-class
 init-param
param-namegreeting/param-name
param-valueKisahairetu/param-value
 /init-param
   /servlet
   
   servlet-mapping
   
  
 

servlet-nameInternationalizedHelloWorld/servlet-name
   
  
 

url-pattern/InternationalizedHelloWorld/url-pattern
   /servlet-mapping
   
   !-- JSPC servlet mappings end --
   
   /web-app
   
   
   
 
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