Yes, g:Europe is the end node and is optional. If no end node is specified, it
will stop at whenever a node doesn't have further values of skos:broader.
You can use spif:shortestSubjectsPath for the inverse direction.
To find the paths to each child, loop over the children:
SELECT *
WHERE {
?child skos:broader g:Europe .
BIND (spif:shortestObjectsPath(?child, skos:broader, g:Europe) AS ?path) .
}
For anything more complex, ADS JavaScript is often a good choice as it gives
you more control:
https://datashapes.org/active/
Holger
> On 19 Feb 2024, at 12:35 am, Marie Valadez <mevalade...@gmail.com> wrote:
>
> Thank you for the example use case. What does g:Europe represent in this
> case? Is that the ending node? Is it necessary to specify the ending node?
> For instance if I wanted to find all the descendants of a concept using the
> inverse of skos:broader and the distance each one is away from the current
> concept, then I wouldn't want to specify a single child concept.
>
> On Sun, Feb 18, 2024 at 3:24 AM Holger Knublauch <hol...@topquadrant.com
> <mailto:hol...@topquadrant.com>> wrote:
>> Here is an example:
>>
>> <PastedGraphic-1.png>
>>
>> where $this is some skos:Concept deep in the hierarchy such as g:Vienna.
>>
>> For easier copy and paste:
>>
>> PREFIX g: <http://topquadrant.com/ns/examples/geography#>
>> PREFIX skos: <http://www.w3.org/2004/02/skos/core#>
>> PREFIX spif: <http://spinrdf.org/spif#>
>>
>> SELECT *
>> WHERE {
>> BIND (spif:shortestObjectsPath(g:Vienna, skos:broader, g:Europe) AS
>> ?path) .
>> }
>>
>> HTH
>> Holger
>>
>>
>>> On 17 Feb 2024, at 7:15 pm, Marie Valadez <mevalade...@gmail.com
>>> <mailto:mevalade...@gmail.com>> wrote:
>>>
>>> The way skos:broader is being used in our case is a tree like structure
>>> with some having multiple parents that can be broader but will point back
>>> to the same main broad concept which branches out to its children,
>>> grandchildren, etc. I need the shortest path from whichever instance is
>>> selected to all of its descendants. All will have the connection to each
>>> other through the skos:broader within the family tree (some can have more
>>> than 1 direct skos:broader concept (parent)).
>>>
>>> Do you have any example documentation on how those functions can be
>>> utilized?
>>>
>>> On Sat, Feb 17, 2024 at 2:44 AM Holger Knublauch <hol...@topquadrant.com
>>> <mailto:hol...@topquadrant.com>> wrote:
>>>> Hi Marie,
>>>>
>>>> we do have some built-in functions including spif:shortestObjectsPath and
>>>> swa:shortestPathsBetweenNodes that may help.
>>>>
>>>> To clarify your requirements, is it true that one of the nodes is always
>>>> an (indirect) parent of the other node, or does the algorithm also need to
>>>> walk in one direction and then in another direction of the tree structure?
>>>>
>>>> And are we talking about tree structures at all, or arbitrary graphs?
>>>>
>>>> Holger
>>>>
>>>>
>>>>> On 16 Feb 2024, at 10:48 pm, Marie Valadez <mevalade...@gmail.com
>>>>> <mailto:mevalade...@gmail.com>> wrote:
>>>>>
>>>>> I have searched and tested out multiple ways to get the distance between
>>>>> two nodes. I want a query that will show the child concepts and how far
>>>>> away they are from the current concept so that I can create a table on a
>>>>> form showcasing this.
>>>>>
>>>>> The following query works if a ?sub concept does not have two connection
>>>>> through skos:broader. But once a ?sub has two parent concepts with the
>>>>> skos:broader it overcounts. I have included a basic example diagram on
>>>>> the issue I am dealing with. Any ideas on how to get an accurate count?
>>>>>
>>>>> SELECT ?sub (count(distinct ?mid) as ?distance)
>>>>> WHERE {
>>>>> $this ^skos:broader* ?mid .
>>>>> ?mid ^skos:broader+ ?sub .
>>>>> }
>>>>> group by $this ?sub
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>
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>>>>
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