would this work?
>>>
a="fe01b8412756fe02fe01b9416239fe02fe01ba41ad88fe02fe01bb41e8e7fe02fe01bc4112fbfe02fe01bd415794fe02"
>>> b=a.replace('fe02fe01','fe02\nfe01').split('\n')
>>> for c in b:
... p
On 2014-12-03 21:36, shweta kaushik wrote:
Hi Joel,
Yes all lines start with fe01 and ends with fe02.
Might this problem not be more easily solved using the re module?
import re
pat_obj = re.compile(r'fe01[0-9a-f]+?fe02')
my_list = pat_obj.findall(string2split)
I tried few things and able t
Hi Joel,
Yes all lines start with fe01 and ends with fe02.
I tried few things and able to split it as list and then I want to split it
into bytes of two like s= fe 01 but when I am taking s[0] then it is
giving only f instead of fe.
On 04-Dec-2014 3:47 am, "Joel Goldstick" wrote:
> On Wed, Dec
On 03/12/14 18:18, shweta kaushik wrote:
I need help for doing this task. I know it will be simple but I am not
able to do it.
Your description of the task is not very precise so I'll
make some guesses below.
output_message_packet= fe01b8412756fe02fe01b9410
I want to
On Wed, Dec 3, 2014 at 1:18 PM, shweta kaushik wrote:
> Hi,
>
> I need help for doing this task. I know it will be simple but I am not able
> to do it.
>
> output_message_packet=
> fe01b8412756fe02fe01b9416239fe02fe01ba41ad88fe02fe01bb410
Hi,
I need help for doing this task. I know it will be simple but I am not able
to do it.
output_message_packet=
fe01b8412756fe02fe01b9416239fe02fe01ba41ad88fe02fe01bb41e8e7fe02fe01bc4112fbfe02fe01bd41
