On 09.07.2014 08:16, Alan Gauld wrote:
On 09/07/14 06:58, Alan Gauld wrote:
list1 = [1, 8, 15]
list2 = [2, 9, 16]
list3 = [[3, 4, 5, 6], [10, 11, 12, 13], [17, 18, 19, 20]]
list4 = [7, 14, 21]
I'm thinking something like
result = []
for L in (list1,list2,list3):
if isinstance(L,list)
On 09/07/14 06:58, Alan Gauld wrote:
list1 = [1, 8, 15]
list2 = [2, 9, 16]
list3 = [[3, 4, 5, 6], [10, 11, 12, 13], [17, 18, 19, 20]]
list4 = [7, 14, 21]
I'm thinking something like
result = []
for L in (list1,list2,list3):
if isinstance(L,list)
result += L
else: result.appen
On 09/07/14 02:44, Robert Nanney wrote:
#!/usr/bin/python
#list_test2.py
list1 = [1, 8, 15]
list2 = [2, 9, 16]
list3 = [[3, 4, 5, 6], [10, 11, 12, 13], [17, 18, 19, 20]]
list4 = [7, 14, 21]
one_list = zip(list1, list2, list3, list4)
first_round = [one_list[x][y] for x in range(len(list3)) for y
Hello All,
I have the following code. The idea is to have one list that contains
all of the items from the different iterable types and maintain the
order of the items.
Python 2.7.6 |Anaconda 2.0.0 (x86_64)| (default, May 27 2014, 14:58:54)
#!/usr/bin/python
#list_test2.py
list1 = [1, 8, 15]
l
