On Sat, 6 Mar 2010 07:17:43 pm you wrote:
> I thought about suggesting using decorators for this, since I've done
> something similar (not exactly exponential backoff, but retrying a
> few times on exception). However, as I started writing the example, I
> got stuck at expressing a generic way to
On Fri, 5 Mar 2010 17:38:08 -0800
Daryl V wrote:
> I have a csv list of data, of the form:
> plot, utmN83_X, utmN83_Y, plot_radius_m
> Spring1,348545,3589235,13.2
> etc.
[...]
> What I want to do is use the first entry in that row (row[0]) as the
> variable name for the instantiated class.
Ther
2010/3/5 Dave Angel
I'm not angry, and I'm sorry if I seemed angry. Tone of voice is hard to
> convey in a text message.
Ok, sorry. I've misunderstood your mail :D
> I'm still not sure whether your confusion is to what the rules are, or why
> the rules were made that way.
WHY the rules are
On Fri, Mar 5, 2010 at 10:48 PM, Hugo Arts wrote:
>
> Except the OP requested pairs (1, 2), (3, 4), i.e. with no duplicate
> elements. Here is a generator that does what you need:
>
> def pairs(seq):
> it = iter(seq)
> try:
> while True:
> yield it.next(), it.next()
> ex
"Daryl V" wrote
What I want to do is use the first entry in that row (row[0]) as the
variable name for the instantiated class.
Thats usually a very bad idea. Not least because all the code that
comes after it would somehow, magically, have to know about this
brand new variable that has appear
Rüdiger Wolf wrote:
> I am trying to Process list elements as consecutive pairs into
> consecutive pairs.
> Any pythonic suggestions?
>
> listin = [1,2,3,4,5,6,7,8,9,10]
> I want to process as consecutive pairs
> 1,2
> 3,4
> 5,6
> 7,8
> 9,10
>>> listin = [1,2,3,4,5,6,7,8,9,10]
>>> it = iter(lis