Victor Binns vic_p...@hotmail.com wrote
I have been trying to add some of the extras with python
such as pywin32 and others.
when i click on setup.py it does not work. I need help on the
problem.
It does not work is pretty vague, can you give more specifics?
How are you running it? What
Quick question to the group to solve an immediate problem and then if anyone
has a dead simple reference on formatting strings it would be greatly
appreciated as I'm finding this to be pretty confusing.
Basically, I need to format a string as an example:
He is {what}.format({wild})
I want to
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Victor Binns
Sendt: 1. februar 2011 01:19
Til: Tutor python
Emne: [Tutor] Need Help in installing MySQLdb-Python
I have Python 2.6.3
I went to the following
Hello,
He is {what}.format(what={wild})
'He is {wild}'
Regards
Karim
On 02/01/2011 09:44 AM, Becky Mcquilling wrote:
Quick question to the group to solve an immediate problem and then if
anyone has a dead simple reference on formatting strings it would be
greatly appreciated as I'm finding
You can always change the precision in decimal. Just an idea
On 31 January 2011 22:23, Richard D. Moores rdmoo...@gmail.com wrote:
Which is accurate to only 16 digits; my Windows Vista calculator gives
2.9231329473018093516404474158812 for 23.45**.34
And using mpmath with Python 2.6
You're missing a . that if your computer is the same as mine, looks like
something left behind by a mosquito
On 1 February 2011 18:33, Karim karim.liat...@free.fr wrote:
Hello,
He is {what}.format(what={wild})
'He is {wild}'
Regards
Karim
On 02/01/2011 09:44 AM, Becky Mcquilling
Complete test copy paste:
karim@Requiem4Dream:~$ python
Python 2.7.1rc1 (r271rc1:86455, Nov 16 2010, 21:53:40)
[GCC 4.4.3] on linux2
Type help, copyright, credits or license for more information.
He is {what}.format(what={wild})
'He is {wild}'
I don't get the missing . ?!
Regards
Karim
Hi Victor,
On 1 February 2011 07:38, Victor Binns vic_p...@hotmail.com wrote:
I have been trying to add some of the extras with python such as pywin32
and others.
when i click on setup.py it does not work.
I need help on the problem.
This is because setup.py is not intended to just be
Becky Mcquilling ladymcse2...@gmail.com wrote
Basically, I need to format a string as an example:
He is {what}.format({wild})
I want to insert wild in place of what and output the resulting text
WITH
the curly braces.
what = 'wild'
Here is {what}.format(what=what)
'Here is wild'
Here
Thanks, as always. It all works.
Becky
On Tue, Feb 1, 2011 at 7:08 AM, Alan Gauld alan.ga...@btinternet.comwrote:
Becky Mcquilling ladymcse2...@gmail.com wrote
Basically, I need to format a string as an example:
He is {what}.format({wild})
I want to insert wild in place of what and
...at least I think it would be nested.
Anyway, I have several widget groups that I want to create inside a frame,
which is inside a class. I started to just do them with copying and pasting,
and changing the values for each one (the first one is commented out, I left it
in so you could see
Hey
I am developing a zero-cross game from the basics of the tkinter. I want
something like this-
We have 4 buttons like 1 2 3 4
i want the output should change on the alternate button hit. Like inorder i
hit-
Button return
1 1
3 0
2 1
4 0
On Tue, Feb 1, 2011 at 3:24 PM, ANKUR AGGARWAL coolankur2...@gmail.comwrote:
Hey
I am developing a zero-cross game from the basics of the tkinter. I want
something like this-
We have 4 buttons like 1 2 3 4
i want the output should change on the alternate button hit. Like inorder i
hit-
I'm looking for a way to flatten lists inside a list literal, kind of like
this:
start = '('
end = ')'
items = ['abc', '+', 'def']
[start, *items, end]
['(', 'abc', '+', 'def', ')']
Of course, the star doesn't work there. Is there any easy,
syntactically-lightweight way to get that output?
I have a function that accepts four arguments, namely startmonth,
startyear, endmonth, and endyear. For example:
startmonth = 8
startyear = 2009
endmonth = 1
endyear = 2010
What would be the most straightforward way to create a list of
year/month pairs from start to end? I want to end up with
On 02/01/2011 03:40 PM, John Simon wrote:
I'm looking for a way to flatten lists inside a list literal, kind of like
this:
start = '('
end = ')'
items = ['abc', '+', 'def']
[start, *items, end]
['(', 'abc', '+', 'def', ')']
Of course, the star doesn't work there. Is there any easy,
On Tue, Feb 1, 2011 at 9:40 PM, John Simon bigjohnexpr...@gmail.com wrote:
I'm looking for a way to flatten lists inside a list literal, kind of like
this:
start = '('
end = ')'
items = ['abc', '+', 'def']
[start, *items, end]
['(', 'abc', '+', 'def', ')']
Of course, the star doesn't work
On 02/01/2011 06:23 PM, Andre Engels wrote:
On Tue, Feb 1, 2011 at 9:40 PM, John Simon bigjohnexpr...@gmail.com wrote:
I'm looking for a way to flatten lists inside a list literal, kind of like
this:
start = '('
end = ')'
items = ['abc', '+', 'def']
[start, *items, end]
['(', 'abc', '+',
On Wed, Feb 2, 2011 at 12:19 AM, Sean Carolan scaro...@gmail.com wrote:
I have a function that accepts four arguments, namely startmonth,
startyear, endmonth, and endyear. For example:
startmonth = 8
startyear = 2009
endmonth = 1
endyear = 2010
What would be the most straightforward way
Andre Engels andreengels at gmail.com writes
Is:
[start] + items + [end]
lightweight enough?
Oh man, duh. I knew it was something simple. Thanks :)
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Elwin Estle chrysalis_reb...@yahoo.com wrote
from Tkinter import *
class Header_item(object):
def __init__(self, lab_text = '', lab_width = 5, ent_width = 5,
grid_row = 1, grid_col = 1):
self.container = Frame()
You haven't specified a parent object for the Frame.
I suspect the
Wayne Werner waynejwer...@gmail.com wrote
def one_or_zero():
x = 0
while True:
x = not x
yield x
In case its not obvious how this iis used in a GUI context...
So for your exampler crweate a state variable somewhere
in your GUI (x in Waynes example) and toggle its value
Hugo Arts hugo.yo...@gmail.com wrote
What would be the most straightforward way to create a list of
year/month pairs from start to end? I want to end up with a list of
tuples like this:
mylist = [(2009, 8), (2009, 9), (2009, 10), (2009, 11), (2009, 12),
(2010, 1)]
That said, you can do
--- On Tue, 2/1/11, Sean Carolan scaro...@gmail.com wrote:
From: Sean Carolan scaro...@gmail.com
Subject: [Tutor] Help with range of months spanning across years
To: Tutor@python.org
Date: Tuesday, February 1, 2011, 6:19 PM
I have a function that accepts four
arguments, namely startmonth,
It bugs me that so many people are quick to jump on the we wont' do
your homework bandwagon -- I was accused of the same thing when I
posted a question to the list myself. I've been programming
professionally for many years but learning Python in my spare time... I
sent this reply to Sean
This sounds somewhat like homework. If it is, that's fine, mention it,
and we will help you. But we won't do your homework for you, so keep
that in mind.
A reasonable assumption but this is actually going in a cgi tool that
I'm using at work. The input comes from pull-down menus on a web
On Wed, Feb 2, 2011 at 2:30 AM, ian douglas ian.doug...@iandouglas.com wrote:
It bugs me that so many people are quick to jump on the we wont' do your
homework bandwagon -- I was accused of the same thing when I posted a
question to the list myself. I've been programming professionally for many
On Wed, Feb 2, 2011 at 2:55 AM, Sean Carolan scaro...@gmail.com wrote:
This sounds somewhat like homework. If it is, that's fine, mention it,
and we will help you. But we won't do your homework for you, so keep
that in mind.
A reasonable assumption but this is actually going in a cgi tool
As far as I can tell from quickly going through documentation, no. At
least, not with a quick and easy function. datetime can represent the
dates just fine, and you can add days to that until you hit your end
date, but adding months is harder. timedelta can't represent a month,
which makes
On Tue, Feb 1, 2011 at 04:29, col speed ajarnco...@gmail.com wrote:
You can always change the precision in decimal. Just an idea
Not exactly sure what you mean. But I just tried using decimal to get
123.2345274523452345235432452345 ** 2.3 to 300 digits:
from decimal import Decimal as D
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