Re: [Tutor] Beginner question

[Ciaran Mooney]

On 10 Aug 2013, at 04:30, eschneide...@comcast.net wrote:

 I've been learning python from the website 'inventwithpython.com', and I'm on 
 a chapter that covers the following code:
 
 import random
 import time
 def displayIntro():
 print('You are in a land full of dragons. In front of you,')
 print('you see two caves. In one cave, the dragon is friendly')
 print('and will share his treasure with you. The other dragon')
 print('is greedy and hungry, and will eat you on sight.')
 print()
 def chooseCave():
 cave = ''
 while cave != '1' and cave != '2':
 print('Which cave will you go into? (1 or 2)')
 cave = input()
  return cave
 def checkCave(chosenCave):
 print('You approach the cave...')
 time.sleep(2)
 print('It is dark and spooky...')
 time.sleep(2)
 print('A large dragon jumps out in front of you! He opens his jaws 
 and...')
 print()
 time.sleep(2)
 friendlyCave = random.randint(1, 2)
 if chosenCave == str(friendlyCave):
 print('Gives you his treasure!')
 else:
 print('Gobbles you down in one bite!')
 playAgain = 'yes'
 while playAgain == 'yes' or playAgain == 'y':
 displayIntro()
 caveNumber = chooseCave()
 checkCave(caveNumber)
 print('Do you want to play again? (yes or no)')
 playAgain = input()
 
 I'm confused about what the line 'checkCave(caveNumber)' does and how it 
 works. I would appreciate any help with this
 
 Thank you,
 
 Eric
 

Hi Eric,

This line calls the method 'checkCave()'. This method takes the argument 
caveNumber (checkCave(caveNumber) , which is a string returned from user input 
generated in the method chooseCave().

In checkCave method, the value (caveNumber) is then used in a if/else statement 
to compare with a random integer (parsed to a string str(frindlyCave))  to 
determine whether you will be eaten or given treasure ;)

Hope that was of some help. 

Ciaran 
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Re: [Tutor] Beginner question

[Jim Mooney]

On 12 August 2013 02:14, Karim Liateni kliat...@gmail.com wrote:

 5ÿt5ÿ6hhhyyyfrrtr

 eschneide...@comcast.net a écrit :

 I've been learning python from the website 'inventwithpython.com', and
 I'm on a chapter that covers the following code:


Just a quick note - not on the algorithm itself. If you run that in some
IDEs, such as Wing101, all the time.sleep()s will concatenate, and all the
prints will then print at once with no delay ;')  If that happens, run it
from the command line or try a different IDE.

Jim
-- 

If you don't know it's impossible, it's easier to do. --Neil Gaiman
The Process is not the Picture...Reality can only be proved to be
weakly-objective. Strong objectivity is a myth. --Bernardo Kastrup
You cannot use logic to justify logic, so logic itself has no basis other
than faith. --Agrippa
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[Tutor] Python Arduino

[Engineering]

Dear All

 

I have designed a small program to control an arduino through python socket
server. The front end is the Javaquery. My HTML code is given below

 

$(function() {

$( #slider ).slider({

  min: 0,

  max: 180,

  step: 10,

  slide: function( event, ui ) {

$( #amount ).val( $ + ui.value );

  }

});

$( #amount ).val( $ + $( #slider ).slider( value ) );

  });

 

My python websocket code is given below

from twisted.internet import reactor

print Using Twisted reactor, reactor.__class__

print

 

from twisted.python import usage, log

from twisted.protocols.basic import LineReceiver

from twisted.internet.serialport import SerialPort

from twisted.web.server import Site

from twisted.web.static import File

 

from autobahn.websocket import listenWS

from autobahn.wamp import WampServerFactory, WampServerProtocol, exportRpc

 

 

class Serial2WsOptions(usage.Options):

   optParameters = [

  ['baudrate', 'b', 9600, 'Serial baudrate'],

  ['port', 'p', 26, 'Serial port to use'],

  ['webport', 'w', 8080, 'Web port to use for embedded Web server'],

  ['wsurl', 's', ws://localhost:9000, 'WebSocket port to use for
embedded WebSocket server']

   ]

 

Can you please help me with the python code . I want the server to write
string which will be sent to the arduino digital pin to control the servo. 

The arduino can have the following in its code

 

if(!Serial.available())

  {

// convert String to int. 

int recievedVal = stringToInt();



//analogWrite(servoPin,recievedVal);

recievedVal = map(recievedVal,0,179,0,179);

webcam.write(recievedVal);

delay(15);

pwmComplete = false;

  }

 

Python side coding help is required

 

CLEANTECH SOLUTION

www.cleantechsolution.in

 

SAVE PAPER , SAVE EARTH

 

 

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Re: [Tutor] Beginner question

[Krishnan Shankar]

def checkCave(chosenCave):
print('You approach the cave...')
time.sleep(2)
print('It is dark and spooky...')
time.sleep(2)
print('A large dragon jumps out in front of you! He opens his jaws
and...')
print()
   time.sleep(2)
friendlyCave = random.randint(1, 2)
if chosenCave == str(friendlyCave):
   print('Gives you his treasure!')
else:
print('Gobbles you down in one bite!')
playAgain = 'yes'
while playAgain == 'yes' or playAgain == 'y':
displayIntro()
caveNumber = chooseCave()
checkCave(caveNumber)
print('Do you want to play again? (yes or no)')
playAgain = input()

Hi,

- Here we are passing the chosen integer (1 or 2) got from chooseCave()
method to checkCave as arguement
- When called in while loop inside checkCave the following happens;
- The statements of approaching the cave and seeing the dragon are
printed with a time interval of 2 secs between each
- Randomly either 1 or 2 is generated by the randint() method of random
module in python.
- That randomly generated integer (1 0r 2) is compared with our integer
input (1 or 2)
- If they match dragon gives us gold. Or else
- We will be eaten by dragon :)

But in the code there is a flaw. input() will evaluate your user input.
i.e. If you give an integer expression it will tell the answer. And when
you provide a number it will take it as int type. See below.

 var = input()
1+2+3
 var
6
 var = input()
2
 type(var)
type 'int'
 var = input()
s
Traceback (most recent call last):
  File stdin, line 1, in module
  File string, line 1, in module
NameError: name 's' is not defined
 var = input()

So since the integer number is checked with string in Line 13, it will run
into infinite loop. If you use raw_input() instead of input() you will be
able to run the example.

Regards,
Krishnan


On Mon, Aug 12, 2013 at 10:25 PM, Jim Mooney cybervigila...@gmail.comwrote:

 On 12 August 2013 02:14, Karim Liateni kliat...@gmail.com wrote:

 5ÿt5ÿ6hhhyyyfrrtr

 eschneide...@comcast.net a écrit :

 I've been learning python from the website 'inventwithpython.com', and
 I'm on a chapter that covers the following code:


 Just a quick note - not on the algorithm itself. If you run that in some
 IDEs, such as Wing101, all the time.sleep()s will concatenate, and all the
 prints will then print at once with no delay ;')  If that happens, run it
 from the command line or try a different IDE.

 Jim
 --

 If you don't know it's impossible, it's easier to do. --Neil Gaiman
 The Process is not the Picture...Reality can only be proved to be
 weakly-objective. Strong objectivity is a myth. --Bernardo Kastrup
 You cannot use logic to justify logic, so logic itself has no basis other
 than faith. --Agrippa


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Re: [Tutor] [Python-Help] Instancing class issue

[Chris Down]

Hi Dino,

On 2013-08-12 20:32, Dino Bektešević wrote:
 def __init__(self, **keys):
 from . import util

 self.keys=keys
 self.load()

 where I don't understand what **keys mean, I've only seen that as **kwargs
 meaning other key words and arguments in examples.

The name of the variable doesn't matter, that's still what it does; you can
think of it as encapsulating any other keyword arguments.

 def foo(bar, **kwargs):
... print(bar: %s % (bar,))
... print(kwargs: %r % (kwargs,))
...
 foo(bar, baz=qux, wibble=wobble)
bar: bar
kwargs: {'baz': 'qux', 'wibble': 'wobble'}


 When I try to instance
 Astrom class by:
 new=Astrom()
 I receive a following error:

Sorry, no idea about this bit, I've never used sdsspy. est of luck sorting this
out.

Chris


pgpR9GydIB2YX.pgp
Description: PGP signature
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Re: [Tutor] Beginner question

[Krishnan Shankar]

But in the code there is a flaw. input() will evaluate your user input.
i.e. If you give an integer expression it will tell the answer. And when
you provide a number it will take it as int type. See below.

Hi,

Ignore my above statements if using Python 3. Sorry my bad. Had a doubt and
went to the site to see the version of python used. My statement above is
correct only if run in Python 2 and not in 3.

Regards,
Krishnan


On Mon, Aug 12, 2013 at 11:01 PM, Krishnan Shankar
i.am.song...@gmail.comwrote:

 def checkCave(chosenCave):
 print('You approach the cave...')
 time.sleep(2)
 print('It is dark and spooky...')
 time.sleep(2)
 print('A large dragon jumps out in front of you! He opens his jaws
 and...')
 print()
time.sleep(2)
 friendlyCave = random.randint(1, 2)
 if chosenCave == str(friendlyCave):
print('Gives you his treasure!')
 else:
 print('Gobbles you down in one bite!')
 playAgain = 'yes'
 while playAgain == 'yes' or playAgain == 'y':
 displayIntro()
 caveNumber = chooseCave()
 checkCave(caveNumber)
 print('Do you want to play again? (yes or no)')
 playAgain = input()

 Hi,

 - Here we are passing the chosen integer (1 or 2) got from chooseCave()
 method to checkCave as arguement
 - When called in while loop inside checkCave the following happens;
 - The statements of approaching the cave and seeing the dragon are
 printed with a time interval of 2 secs between each
 - Randomly either 1 or 2 is generated by the randint() method of
 random module in python.
 - That randomly generated integer (1 0r 2) is compared with our
 integer input (1 or 2)
 - If they match dragon gives us gold. Or else
 - We will be eaten by dragon :)

 But in the code there is a flaw. input() will evaluate your user input.
 i.e. If you give an integer expression it will tell the answer. And when
 you provide a number it will take it as int type. See below.

  var = input()
 1+2+3
  var
 6
  var = input()
 2
  type(var)
 type 'int'
  var = input()
 s
 Traceback (most recent call last):
   File stdin, line 1, in module
   File string, line 1, in module
 NameError: name 's' is not defined
  var = input()

 So since the integer number is checked with string in Line 13, it will run
 into infinite loop. If you use raw_input() instead of input() you will be
 able to run the example.

 Regards,
 Krishnan


 On Mon, Aug 12, 2013 at 10:25 PM, Jim Mooney cybervigila...@gmail.comwrote:

 On 12 August 2013 02:14, Karim Liateni kliat...@gmail.com wrote:

 5ÿt5ÿ6hhhyyyfrrtr

 eschneide...@comcast.net a écrit :

 I've been learning python from the website 'inventwithpython.com', and
 I'm on a chapter that covers the following code:


 Just a quick note - not on the algorithm itself. If you run that in some
 IDEs, such as Wing101, all the time.sleep()s will concatenate, and all the
 prints will then print at once with no delay ;')  If that happens, run it
 from the command line or try a different IDE.

 Jim
 --

 If you don't know it's impossible, it's easier to do. --Neil Gaiman
 The Process is not the Picture...Reality can only be proved to be
 weakly-objective. Strong objectivity is a myth. --Bernardo Kastrup
 You cannot use logic to justify logic, so logic itself has no basis
 other than faith. --Agrippa


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[Tutor] Python Programming for the Absolute Beginner - Chap 7 Q: 2

[Zack Hasanov]

Hello,

 

I am a python newbie.  I am reading this book (Python Programming for the
Absolute Beginner).  I am on Chapter 7, Question 2.  

 

Improve the Trivia Challenge game so that it maintains a high-scores list
in a file. The program should record the player's name and score. Store the
high scores using a pickled object.

I have the following code so far:

 

def high_score():

Records a player's score

 

high_scores = []

 

#add a score // Do current stuff for adding a new score...

name = input(What is your name? )

player_score = int(input(What is your score? ))

entry = (name, player_score)

high_scores.append(entry)

high_scores.sort(reverse=True)

high_scores = high_scores[:5]   # keep only top five

 

# dump scores

f = open(pickles1.dat, wb)

pickle.dump(high_scores, f)

f.close()

 

f = open(pickles1.dat, rb)

high_scores = pickle.load(f)

print(high_scores)

f.close()

 

When I execute this program in the main() program I get only the existing
single name, player_score list combination stored in the pickles1.dat file.

 

Can someone walk me through how it can store all the values each time the
program is ran?

 

Thanks,

Zack H.

 

 

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[Tutor] Instancing class issue

[Dino Bektešević]

Hello,

I have an unusual problem when I try to instance a class Astrom from a set
of tools for astronomy SDSSPY. Here's the link to the project page:
http://code.google.com/p/sdsspy/
and this is the class I'm having problems instancing:
http://code.google.com/p/sdsspy/source/browse/sdsspy/astrom.py
I'm running LucidLynx (You are using Ubuntu 10.04 LTS released in April
2010 and supported until April 2013.) on a Oracle VirtualBox v4.2.12 and
I'm using Python 2.6.5. (reason being that I'm also importing various other
modules like esutil, scipy, numpy of which some don't work properly on
never version, or so I have been informed). Home OS is win7 64bit.
I'm not new to programming but don't consider me an expert, or even amateur
in python, most about python I learned from diveintopython and other random
sources I used as I got further into it solving problems.

Ok now onto the problem itself:
There's a method pix2eq in the class Astrom I wish to use. However because
it's inside a class obviously I need to instance it because you can only
use methods on class instances. When I read the Astrom class definition
there clearly states:

def __init__(self, **keys):
from . import util

self.keys=keys
self.load()

where I don't understand what **keys mean, I've only seen that as **kwargs
meaning other key words and arguments in examples. When I try to instance
Astrom class by:
new=Astrom()
I receive a following error:

Traceback (most recent call last):
  File pyshell#7, line 1, in module
novi=Astrom()
  File /usr/local/lib/python2.6/dist-packages/sdsspy/astrom.py, line 44,
in __init__
self.load()
  File /usr/local/lib/python2.6/dist-packages/sdsspy/astrom.py, line 266,
in load
raise ValueError(send run= and camcol=)
ValueError: send run= and camcol=

which seems pretty straight forward except that I don't see it requiring me
to do so anywhere and that when I try to follow instructions:

new = Astrom(run=2888, camcol=1)

(both run 002888 and camcol 1 exist I have the images I need downloaded on
my drive already) I recieve error about my enviroment:

Traceback (most recent call last):
  File pyshell#11, line 1, in module
novi = Astrom (run=2888, camcol=1)
  File /usr/local/lib/python2.6/dist-packages/sdsspy/astrom.py, line 44,
in __init__
self.load()
  File /usr/local/lib/python2.6/dist-packages/sdsspy/astrom.py, line 270,
in load
fname=files.filename('photoField', **keys)
  File /usr/local/lib/python2.6/dist-packages/sdsspy/files.py, line 274,
in filename
return fs.filename(ftype, run, camcol, field, **keys)
  File /usr/local/lib/python2.6/dist-packages/sdsspy/files.py, line 479,
in filename
f = expand_sdssvars(f, run=run, camcol=camcol, field=field, **keys)
  File /usr/local/lib/python2.6/dist-packages/sdsspy/files.py, line 870,
in expand_sdssvars
raise ValueError(err)
ValueError: There were unexpanded variables: '$PHOTO_REDUX/runList.par',
there may be no such run but you might try sending the rerun

except search doesn't pop-out any runList.par files anywhere.
Is it something I'm doing wrong or is it something I should contact the
author Mr. Sheldon personally? Any comment about the class is appreciated,
including the Astrom(object) type inheritance.

Help is greatly appreciated,
Dino Bektešević
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Re: [Tutor] Python Programming for the Absolute Beginner - Chap 7 Q: 2

[Alan Gauld]

On 12/08/13 01:52, Zack Hasanov wrote:


I have the following code so far:

def high_score():
 high_scores = []

 name = input(What is your name? )
 player_score = int(input(What is your score? ))
 entry = (name, player_score)
 high_scores.append(entry)
 high_scores.sort(reverse=True)
 high_scores = high_scores[:5]   # keep only top five


Note that you never read the stored values from your pickle file you 
just add a single value.




 # dump scores
 f = open(pickles1.dat, wb)
 pickle.dump(high_scores, f)
 f.close()


This then dumps that single value to the file overwriting
anything that might have already been there.


 f = open(pickles1.dat, rb)
 high_scores = pickle.load(f)
 print(high_scores)


You then load the new value and print it.


When I execute this program in the main() program I get only the
existing single name, player_score list combination stored in the
pickles1.dat file.


I have no idea how you call this. Presumably from within a loop?
But because you never read in the stored values before writing the new 
you only ever get the last value stored.


You need to insert code like your last block above at the top of the 
function to pre-populate high_scores before adding the new entry.


Once you get that working we can look at tidying up some
of the unnecessary code that will be left over, but lets
get it working first!

HTH
--
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/

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Re: [Tutor] How to access a method defined in one class from another class (which is a thread) in Python3?

[SM]

Hi Alan,
Thanks, very much, for your time answering my question. I ended up using
global variables for all the attributes I had to share between the
MainWindow class and the thread, and it worked. I am sure there are better
alternatives, but since it was just a couple of attributes, the code looks
ok.
Some responses  in line at [SM]

On Sun, Aug 11, 2013 at 12:05 PM, Alan Gauld alan.ga...@btinternet.comwrote:

 On 09/08/13 16:50, SM wrote:

 Sorry I only just picked this up.


  (ex: self.tab_fw = QtGui.QWidget(), self.tab_ann = QtGui.QWidget(),
 etc), its own textEdit window and its own progress bar widget.
 All the tabs are defined within this single class - they are not
 instances of the class, as the tabs are distinct from each other. All of
 that is working really well.


 OK, I'll assume the structure looks like

 MainGUIWindow
 - Tab1
   - TextEdit1
   - ProgressBar1
   - any other widgets on tab1
 - Tab2
   - TextEdit2
   - ProgressBar2
   - any other widgets on tab2
 - Tab3
   - TextEdit3
   - ProgressBar3
   - any other widgets on tab3

[SM] Yes


 And that both the TextEdit and progress bar widgets are part of
 the Qt framework/library? So there are 3 distinct progress bar instances,
 one per tab?


[SM]: Yes, that is right.



  an added feature, I am now asked to have a progress bar widget
 which appears when an operation is going on, to tell the user that
 he/she has to wait.


 Is this an extra (4th?) progress bar or is this the ones already described
 as being in the tabs?


[SM] The latter. There are just 3 tabs and 3 progress bars


 Also, when you say appears do you mean its invisible until the operation
 starts? Or is it visible but inactive (maybe greyed out?)

[SM] Wrong choice of word on my part.  I should have said,  widget which
swings horizontally



  [SM]: Yes. I shouldn't say duplicated, but each tab has a different
 progress bar of its own. In the example, I was quoting the code for just
 on tab. The others will be implemented similarly.


 OK So I'm again going to assume:

 A total of 1 progress bar per tab. The added feature is what these bars
 are addressing?

[SM]: yes



  So I am running two threads - first one is the progressbar
 widget which has a rectangular slab spinning sideways to
 indicate that the operation is going on.


 I usually expect a progress bar to indicate the percentage complete but
 this sounds like its just a spinning eggshell activity indicator. Is that
 correct? You have no progress value indication?


[SM] Yes, it is more of a egg-whatever It just spins horizontally as
opposed to showing the percentage of work done. That is part of the
requirement.



  The second thread is the one which is actually doing the operation.

  I have a flag that the second thread sets after the job is done

 OK, again I'll assume we are dealing with just an activity indicator not a
 value display.


[SM] yes



  and stops spinning and gets out of the loop when the flag is set.
  I
 have that working as well.


 OK, Good the picture is building.


  [SM]: I did start out with a timer. But due to my lack of experience
 with usage of timer in Python, the code I wrote was running sequentially


 That sounds like you tried to use a Python native timer. Normally in a GUI
 the toolkit (Qt in this case) provides a timer event that triggers
 via the normal event mechanism. You set the timer, the event arrives and
 you do something then reset the timer for the next time round.

 I found this page that describes the Qt approach (which includes
 multi-shot timers) and links to more detailed examples etc.

 http://qt-project.org/doc/qt-**4.7/timers.html#id-fd46b213-**
 376e-4636-a7d2-8ae899de1e11http://qt-project.org/doc/qt-4.7/timers.html#id-fd46b213-376e-4636-a7d2-8ae899de1e11


[SM] Thanks, very much, for the link. I will go over it. In my opinion, if
the timer works, using it is less complicated than using threads.

Thanks!
-SM


 The code is in C++ but should translate easily to python and PyQt.

 HTH

 --
 Alan G
 Author of the Learn to Program web site
 http://www.alan-g.me.uk/

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