hi all. i'm trying to write a simple program. i'm using python 3.4
let us say i have
s="2*3+3(8-4(5+6+9))+2+3+3(4/4)"
i want to find expression enclosed in brackets.
i want outputs to be like:
(8-4(5+6+9))
(5+6+9)
(4/4)
i've tried where denotes an indentation level :
#first part
sbracket
On 16 Apr 2017 10:01, "Palm Tree" wrote:
Sorry for late reply.
We usually organise python challenges.
Once we organise a gui calculator challenge.
You can view the submissions on my blog here:
https://abdurrahmaanjanhangeer.wordpress.com/gui-py-
calculator-challenge-19-1-17/
On 1
-- Forwarded message --
From: "Palm Tree"
Date: 16 Apr 2017 10:07
Subject: Re: [Tutor] bracket issue
To: "Peter Otten" <__pete...@web.de>
Cc:
Ok thanks for the answers. Perfect.
Just to clarify why i wanted recursion was that well coming to compiler
for entering digits on the canva i think better create a sort of sudoku
generator and display it on the canva in a create_text object.
On 20 Apr 2017 05:24, "Phil" wrote:
> I'm looking for ideas here.
>
> A working solution for my sudoku solver is a 9 x 9 grid of entry boxes but
> it looks a bit
Sorry i'm a bit new to automated testing.
I have explored python wide and deep but can someone just tell me why as a
coder i need automated testing?
i have tried some googling but the explanations are a bit crazy.
thanks.
___
Tutor maillist - Tutor@p
Hum i also suggest you get more experience with python
think of a project and learn while doing it. thus you'll get motivation
while at the same time doing something useful which you could reuse in the
future.
else,
me for bs4 i googled what i needed. I also put an increasing variable to
ease we
