Re: [Tutor] Code for python game
hi, tracey, are you allowed to use python sets? if so, you should take a look at them and their methods: https://docs.python.org/3.5/tutorial/datastructures.html?highlight=data%20structures#sets best, james From: Tutor [tutor-bounces+jderry=mail.utexas@python.org] on behalf of tracey jones-Francis [drtraceyjo...@hotmail.com] Sent: Wednesday, October 12, 2016 12:40 PM To: tutor@python.org Subject: [Tutor] Code for python game Im in the middle of designing a game in python, im quite new to using it and am struggling with a certain bit of code. I want to have a function that will ignore certain words that i have specified in a dictionary. I have tried so many different types of code but can't seem to return just the keywords i want. the dictionary is called skip_words and has about 20 different strings in. so far i came up with: def filter_words(words, skip_words): word = words.strip(skip_words) return word The function should read an input such as help me please and filter out the words "please" and "me" as they are in the dictionary and just return the word help as the input. >>>filter_words(["help", "me", "please"], ["me", "please"]) ['help'] That doesn't work but i just assume it is a very simple bit of code. any suggestions of a way that works? Thanks:) T ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Code for python game
On 12/10/16 18:40, tracey jones-Francis wrote: > I want to have a function that will ignore certain words that > i have specified in a dictionary. > the dictionary is called skip_words and has about 20 different strings in. We shouldn't care inside the function what the external data is called, we just write it to accept a list of words (its not a dictionary, it is a list). > def filter_words(words, skip_words): >word = words.strip(skip_words) >return word > filter_words(["help", "me", "please"], ["me", "please"]) > ['help'] Your code above cannot work because it tries to strip() a list of words. You can only strip one string at a time, so the first thing you need is a loop that tests each word. Secondly strip() removes characters from your string but that's not necessarily needed here (it depends how you build the input list...) Let's assume the words are already stripped and in lowercase. Now, for each word in your input you want to see if it is in the skip list. If not add it to your output list - you haven't got one of those yet so you'll need to create one. Once you have tested all the input words you can return the result list. I It should look something like (untested): def filter_words(words, skips): result = [] for word in words: if word not in skips: results.append(word) return result If you know about list comprehensions you can do that all in one line! -- Alan G Author of the Learn to Program web site http://www.alan-g.me.uk/ http://www.amazon.com/author/alan_gauld Follow my photo-blog on Flickr at: http://www.flickr.com/photos/alangauldphotos ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
