Tiemo,
Is the task to compare two CSV files regardless of their line endings? If you
don’t care what the line endings are, as Brian points out, using “file:” to
read them will convert all line endings to just LF. Then there is no problem
comparing, right?
.Jerry
> On Apr 18, 2018, at 6:52 AM,
One other consideration is how you are opening the file. Using “file” will
end up converting to just LF. You will need to use “binfile” to examine the
line endings native in the file.
On Wed, Apr 18, 2018 at 8:11 AM dunbarx via use-livecode <
use-livecode@lists.runrev.com> wrote:
> Tiemo.
>
> I
Tiemo.
I guess I do not understand.
put charToNum(the number of chars of line (lineOfInterest + 1) of yourText)
into tChar
Then tChar can be compared to the "tChar" of any other line.
Craig
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e: How to get the line break char?
Hi.
You cannot ask for the "last" char of a line, because LC will give you the
last "non-control" char.
Say you have the below text in a field:
abc
def
So the last char of line 1 is "c". But the number of chars of that text
snippet
14:50
An: use-revolut...@lists.runrev.com
Cc: dunbarx <dunb...@aol.com>
Betreff: Re: How to get the line break char?
Hi.
You cannot ask for the "last" char of a line, because LC will give you the
last "non-control" char.
Say you have the below text in a field:
abc
def
Hi.
You cannot ask for the "last" char of a line, because LC will give you the
last "non-control" char.
Say you have the below text in a field:
abc
def
So the last char of line 1 is "c". But the number of chars of that text
snippet is 7
But numToChar(char 4 of fld 1) = 10. That is a return
Hello,
I want to compare two CSV files and I suspect that there is a difference in
the kind of line break. With charToNum(last char of line 1 of field "foo") I
can compare the last visible char of each line, but how can I get and
analyse the line break char that is used?
Thanks
Tiemo
