On 25/05/2024 16:13, Mike Kerner via use-livecode wrote:
(to alex's question)
* quicken date shortcuts
quicken has/had these very nifty ways of handling date inputs, to make
entry faster.
if you enter a numeral, like 26, it means that date of this month.
similarly, month/date e.g. 5/25 is
(to alex's question)
> * quicken date shortcuts
quicken has/had these very nifty ways of handling date inputs, to make
entry faster.
if you enter a numeral, like 26, it means that date of this month.
similarly, month/date e.g. 5/25 is 5/25 of this year.
"T" is today
"+" to increment the date field
The single most important feature of LiveCode is this list. Thank you, Bob,
Alex, Mike and Andreas
Roger
> On May 24, 2024, at 8:26 AM, Bob Sneidar via use-livecode
> wrote:
>
> Actually:
>
> put tList into tTest — so you don’t lose the original contents of tList
> filter items of tTest
Actually:
put tList into tTest — so you don’t lose the original contents of tList
filter items of tTest with 2
put the number of items of tTest
Bob S
> On May 24, 2024, at 8:23 AM, Bob Sneidar via use-livecode
> wrote:
>
> Filter items of tList with 2;put the number of items of tList
>
>
Filter items of tList with 2;put the number of items of tList
Bob S
> On May 23, 2024, at 7:07 PM, Roger Guay via use-livecode
> wrote:
>
>
> Hi all,
>
> Please, what’s the easiest way to return the total number of a given repeated
> number in a list of numbers? IOW, how many times is 2
On 24/05/2024 13:35, Mike Kerner via use-livecode wrote:
i LOVE all of these solutions.
chunking is so great.
in every language i use, there are two things i always implement:
* chunking
Yes.
* quicken date shortcuts
Alex.
___
i LOVE all of these solutions.
chunking is so great.
in every language i use, there are two things i always implement:
* chunking
* quicken date shortcuts
On Fri, May 24, 2024 at 2:56 AM Andreas Bergendal via use-livecode <
use-livecode@lists.runrev.com> wrote:
> Another way to do it is this:
>
Another way to do it is this:
function countOccurrences pString
repeat for each item tItem in pString
add 1 to tFrequencyArray[tItem]
end repeat
return tFrequencyArray
end countOccurrences
To get the number of 2’s, just extract tFrequencyArray[2] etc.
The advantage is that you
Very clever, Mike. I never thought to use itemDelimiter this way. I’ll have to
play with this.
Thanks very much,
Roger
> On May 23, 2024, at 7:37 PM, Mike Kerner via use-livecode
> wrote:
>
> just spitballing:
> let's call our containers "tSearchingFor" and "tSearchString"
>
> *set* the
Probably not the shortest approach, but I’d probably do either this…
function countItemRepsInList pList, pItem
replace comma with cr in pList
filter pList with pItem
return (the number of lines in pList)
end countItemRepsInList
or this
function countItemRepsInList pList, pItem
put 0
just spitballing:
let's call our containers "tSearchingFor" and "tSearchString"
*set* the itemDelimiter to comma & tSearchString & comma
*put* the number of items in tSearchingFor - 1 into tNum
*if* tSearchString begins with tSearchingFor & comma *then* *add* 1 to tNum
*if* tSearchString ends
Hi all,
Please, what’s the easiest way to return the total number of a given repeated
number in a list of numbers? IOW, how many times is 2 repeated in a list
containing 1,2,3,2,4,2,5,2,8 etc. Appreciate your help.
Thanks,
Roger
___
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