if someone
> is
> > > scraping memory you have bigger problems.
> > >
> > > Ralph DiMola
> > > IT Director
> > > Evergreen Information Services
> > > rdim...@evergreeninfo.net
> > >
> > > -----Original Message-----
> > &g
gt; > Evergreen Information Services
> > rdim...@evergreeninfo.net
> >
> > -Original Message-
> > From: use-livecode [mailto:use-livecode-boun...@lists.runrev.com] On
> > Behalf
> > Of Tom Glod via use-livecode
> > Sent: Thursday, December 30, 2021
alf
> Of Tom Glod via use-livecode
> Sent: Thursday, December 30, 2021 4:34 PM
> To: How to use LiveCode
> Cc: Tom Glod
> Subject: Re: Is it normal to not be able to set script of objects in an
> encrypted stack?
>
> HmmmI hear you, that makes sense.
>
> On the fli
e
Sent: Thursday, December 30, 2021 4:34 PM
To: How to use LiveCode
Cc: Tom Glod
Subject: Re: Is it normal to not be able to set script of objects in an
encrypted stack?
HmmmI hear you, that makes sense.
On the flip side, as soon as I want to set the script of a button, I'm
doomed to hav
tom trilled,
> On the flip side, as soon as I want to set the script of a button, I'm
> doomed to have my code remain readable. I gotta think of a workaround for
> why I was setting the script to begin with.
Now I’m wondering . . . can you set the behavior of the object in the protected
stack to
HmmmI hear you, that makes sense.
On the flip side, as soon as I want to set the script of a button, I'm
doomed to have my code remain readable. I gotta think of a workaround for
why I was setting the script to begin with.
Thanks MIke.
On Thu, Dec 30, 2021 at 2:43 PM Mike Kerner via use-li
I would hope that would be the behavior. It would also make it harder for
your stack to get borked by someone else.
If I was trying to break that behavior I would try to put the code into a
variable, encrypt the variable using the password, then set the script of
the object to the encrypted version
Hi Folks,
Today I found out that if I put a password on my stack, any code that sets
the script of an object in that stack receives an execution error when
running as standalone.
Why is this so?
And is there a workaround?
Thanks,
--
Tom Glod
Founder & Developer
MakeShyft R.D.A (www.makeshyft
