Re: mobile acceleration/rotation

2016-01-14 Thread Ben Rubinstein
Thanks Jim. So if the device is vertical at rest (y=-1), and falls down vertically, it won't register any acceleration because it's already measuring the maximum in that axis? In short, it's static acceleration rather than dynamic acceleration, is that correct? Many thanks, Ben On

Re: mobile acceleration/rotation

2016-01-14 Thread Consensus IMAP
Hopefully, I've got this right but. I think of it as the "apparent" acceleration a mass attached to phone feels relative to the body of the device. At rest, if it wasn't attached, it would slide down the inside of the device and end up rattling inside the case. The force trying to make that

Re: mobile acceleration/rotation

2016-01-14 Thread Peter M. Brigham
On Jan 14, 2016, at 6:06 AM, Ben Rubinstein wrote: > So if the device is vertical at rest (y=-1), and falls down vertically, it > won't register any acceleration because it's already measuring the maximum in > that axis? > > In short, it's static acceleration rather than dynamic acceleration,

Re: mobile acceleration/rotation

2016-01-14 Thread Peter M. Brigham
On Jan 14, 2016, at 6:06 AM, Ben Rubinstein wrote: > So if the device is vertical at rest (y=-1), and falls down vertically, it > won't register any acceleration because it's already measuring the maximum in > that axis? > > In short, it's static acceleration rather than dynamic acceleration,

RE: mobile acceleration/rotation

2016-01-13 Thread Jim MacConnell
Short answer: Gravity. The device can't measure actual acceleration. It measures the forces on sensors in 3 axes. One of those axes will feel force from gravity. That's the 1. Jim -Original Message- From: Ben Rubinstein [mailto:benr...@cogapp.com] Sent: Wednesday, January 13, 2016 5:08