No Scott you are missing a bit of information here. Try this:
on mouseUp
put "This is a test" into theArray[1]
put "This is a second test" into theArray[2]
put "This is a third test" into theArray[3]
delete variable theArray[2]
put the keys of theArray
end mouseUp
What you will get
Try instead:
put the keys of theArray into myKeys
put "2" is in myKeys
See what you get.
Bob
On Sep 1, 2011, at 2:53 AM, Scott Rossi wrote:
> Sorry, I don't know the correct verbiage here...
>
> If I script this:
>
> put "A" into theArray[1]
> put "B" into theArray[2]
> put "C" into theArray
I can put "put theArray[2]" into the message box and get empty, and I do not
even HAVE an array called theArray! :-)
Bob
On Sep 1, 2011, at 5:13 AM, Colin Holgate wrote:
> Try this in the multiline message box:
>
> put "A" into theArray[1]
> put "B" into theArray[2]
> put "C" into theArray[3]
Scott Rossi wrote:
Recently, Richard Gaskin wrote:
The delete is fine; the problem is in the display of the results.
If you use:
put theArray[1] &"*"&theArray[2] &"*"& theArray[3]
...you'll get the empty entry for theArray[2]. The variable theArray
still exists, but there's nothing in t
Recently, Jacque Landman Gay wrote:
>> From what you're saying, it sounds like I need to put the remaining elements
>> of the array into a temporary variable and then replace the original array.
>
> If that's what you need, then it might be easier to just combine the
> array, remove the line you
On Thu, Sep 1, 2011 at 12:18 PM, J. Landman Gay wrote:
> On 9/1/11 9:10 AM, Scott Rossi wrote:
>
> From what you're saying, it sounds like I need to put the remaining
>>> elements
>>>
>> of the array into a temporary variable and then replace the original
>> array.
>>
>
> If that's what you need,
On 9/1/11 9:10 AM, Scott Rossi wrote:
From what you're saying, it sounds like I need to put the remaining elements
of the array into a temporary variable and then replace the original array.
If that's what you need, then it might be easier to just combine the
array, remove the line you don't
Yes, the "I think" part of what I said meant that to me it had over complicated
things. Glad to hear that it was easy to understand for the others, and at
least I had the personal breakthrough of realizing that anArray[10] doesn't
refer to the tenth position of an array.
On Sep 1, 2011, at 10:
Recently, Richard Gaskin wrote:
> The delete is fine; the problem is in the display of the results.
>
> If you use:
>
>put theArray[1] &"*"&theArray[2] &"*"& theArray[3]
>
> ...you'll get the empty entry for theArray[2]. The variable theArray
> still exists, but there's nothing in that slo
Collin,
Perhaps to you I was over complicating things, but as I
see it, that is what he was asking for.
If you have nothing nice to
say . . .
Mike
P.S. I am not an admin - when I joined the live code
summer academy, they auto-assigned this forum name to me - it's not by
my choice.
On
On 1 Sep 2011, at 14:48, Admin wrote:
> So, if A,B,C,D is the array with positions 1,2,3,4
>
> and you
> delete array variable 2
>
> It will now look like this:
>
> A,C,D
>
> and the
> array numbers are now:
>
> 1,3,4
>
> He needs it to be
>
> A,C,D
>
> and
>
> 1,2,3
Looking ba
I think Mike's explanation over complicated things!
I now understand what Dave was saying, and the problem stems from us humans
reading a "1" as an index into the array, and not a key of the array.
In other languages you could say:
put "hello" into theArray[10]
and that array would now have te
Scott Rossi wrote:
If I script this:
put "A" into theArray[1]
put "B" into theArray[2]
put "C" into theArray[3]
And then script this:
delete variable theArray[2]
I essentially get an array with entries that look like this:
A
C
How can I collapse (?) the array after deleting element 2 so
I totally get what the OP wants, code-wise, I just cannot help make
it happen, but perhaps I can put it in my terms and help someone more
knowledgeable than me help him.
What he is saying, is that when a
variable is deleted from within the array, he needs the entire array
re-ordered (sorted)
On 1 Sep 2011, at 14:16, Dave Cragg wrote:
> It seems using any key on an existing array will produce an empty value. (I
> don't know if that's how it should behave. I guess the alternative would be
> throwing an error.)
Update: it seems the array doesn't even need to exist. This also produces
On 1 Sep 2011, at 13:13, Colin Holgate wrote:
> Try this in the multiline message box:
>
> put "A" into theArray[1]
> put "B" into theArray[2]
> put "C" into theArray[3]
> delete variable theArray[2]
> put theArray[1] &"*"&theArray[2] &"*"& theArray[3]
>
>
> You'll see that although theArray[2
Try this in the multiline message box:
put "A" into theArray[1]
put "B" into theArray[2]
put "C" into theArray[3]
delete variable theArray[2]
put theArray[1] &"*"&theArray[2] &"*"& theArray[3]
You'll see that although theArray[2] is deleted, its position is still kept.
The way the dictionary de
On 1 Sep 2011, at 10:53, Scott Rossi wrote:
> Sorry, I don't know the correct verbiage here...
>
> If I script this:
>
> put "A" into theArray[1]
> put "B" into theArray[2]
> put "C" into theArray[3]
>
>
> And then script this:
>
> delete variable theArray[2]
>
>
> I essentially get an arr
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